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2 years ago

14

Match each space mission with the correct milestone.

2 answers:

MrRissso [65]2 years ago

6 0

Matching each space mission with the correct milestone

First animal in space ____________ Sputnik 2
first person in space ____________ Vostok 1
first person on the moon _________ Apollo 11
first man-made object in space ____ Sputnik 1
first American in space __________ Freedom 7
first space station ______________ Salyut

<h3>Meaning of space mission</h3>

A space mission is a mission that takes an individual, animal, a thing or material out of earth using a spaceship. This mission is always carried out with a desire to find out more about the galaxy earth is a member of and to learn about other planets.

In conclusion, the list above is the accurate Matching of each space mission with the correct milestone.

Learn more about Space mission: brainly.com/question/1298543

#SPJ1

sukhopar [10]2 years ago

3 0

Answer:

See attachment below, Hope it helps!

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4 years ago

uniform disk with mass 40.0 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is station

Alex787 [66]

Answer:

The magnitude of the tangential velocity is $v= 0.868 m/s$

The magnitude of the resultant acceleration at that point is $a = 4.057 m/s^2$

Explanation:

From the question we are told that

The mass of the uniform disk is $m_d = 40.0kg$

The radius of the uniform disk is $R_d = 0.200m$

The force applied on the disk is $F_d = 30.0N$

Generally the angular speed i mathematically represented as

$w = \sqrt{2 \alpha \theta}$

Where $\theta$ is the angular displacement given from the question as

$\theta = 0.2000 rev = 0.2000 rev * \frac{2 \pi \ rad }{1 rev}$

$=1.257\ rad$

$\alpha$ is the angular acceleration which is mathematically represented as

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

The moment of inertial is mathematically represented as

$I = \frac{1}{2} m_dR^2_d$

Substituting values

$I = 0.5 * 40 * 0.200^2$

$= 0.8kg \cdot m^2$

Considering the equation for angular acceleration

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

Substituting values

$\alph$ $\alpha = \frac{(30.0)(0.200)}{0.8}$

$= 7.5 rad/s^2$

Considering the equation for angular velocity

$w = \sqrt{2 \alpha \theta}$

Substituting values

$w =\sqrt{2 * (7.5) * 1.257}$

$= 4.34 \ rad/s$

The tangential velocity of a given point on the rim is mathematically represented as

$v = R_d w$

Substituting values

$= (0.200)(4.34)$

$v= 0.868 m/s$

The radial acceleration at hat point is mathematically represented as

$\alpha_r = \frac{v^2}{R}$

$= \frac{0.868^2}{0.200^2}$

$= 3.7699 \ m/s^2$

The tangential acceleration at that point is mathematically represented as

$\alpha _t = R \alpha$

Substituting values

$\alpha _t = (0.200) (7.5)$

$= 1.5 m/s^2$

The magnitude of resultant acceleration at that point is

$a = \sqrt{\alpha_r ^2+ \alpha_t^2 }$

Substituting values

$a = \sqrt{(3.7699)^2 + (1.5)^2}$

$a = 4.057 m/s^2$

7 0

3 years ago

A car travels 60 km in the first 2 hours and 68 km in the next 2 hours.

ZanzabumX [31]

Answer:32km/hr

Explanation:

Speed=distance/time

Speed=60/2 =30km/hr speed=68/2=34km/he

Average speed=(30+34)/2 =64/2=32km/hr

4 0

3 years ago