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andriy [413]
2 years ago
10

The black graph is the graph of y=f(x). Choose the equation for the red graph.

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

Answer:

y-1 = f(x)

Step-by-step explanation:

Here, we want to choose the equation for the ref graph

The red graph as we can see is above the black

This means it is more positive

The difference between the two is just 1 unit

By the addition of 1 to the y-value of the black graph, we get the red

Thus, we have that;

y- 1 = f(x)

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x=21

Step-by-step explanation:

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Step-by-step explanation:

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What is the slope of the line represented by the equation y = 4/5 x -3? A-1 B-4/5 C4/5 D3
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Option C

<u>ANSWER: </u>

For the given equation slope is \frac{4}{5} so the correct option is c.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{4}{5} x-3$

We need to find the slope of the given equation.

Above given equation is in the form of slope intercept form, i.e. y = mx + c

Where m is the slope and c is the intercept made on axis by this line.

By comparing the given equation and the general form, we can conclude that,  m = \frac{4}{5} and c = -3

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3 years ago
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How to solve this problem step by step. Make brainliest answer if its done. Please
sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

\frac{y2 - y1}{x2 - x1}

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>

SUB IN COORDINATES OF D AND E

\frac{1 - 2}{ - 1 - 2}

therefore the gradient of DE is 1/3.

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>

<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>

<em>\frac{ - 2 - 0}{ - 3 - 3}</em>

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

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3 years ago
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masya89 [10]

Answer:

its c

Step-by-step explanation:

By the converse of the hinge theorem, mAngleS > mAngleC.

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