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zalisa [80]
3 years ago
10

A data set has 5,500 observations. When the data are represented in a relative frequency distribution, the relative frequency of

a given interval is 0.15. The frequency in this interval is equal to:_________
Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

The appropriate solution is "825".

Step-by-step explanation:

Given that,

Total observations,

= 5,500

Relative frequency,

= 0.15

As we know,

⇒ Relative \ frequency=\frac{Frequency \ of \ item}{Total}

or,

⇒ Frequency=Relative \ frequency\times Total

By putting the values, we get

⇒                   =0.15\times 5500

⇒                   =825

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Montano1993 [528]
Anddddddddddddd? what else?
3 0
3 years ago
If 75% of a class answered the 1st question on a certain test correctly, 55% answered the 2nd question on the test correctly and
guapka [62]
100-20=80
80-75=5
75-55=20
20+5=25
Answer=25
6 0
3 years ago
If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​
marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

                          =\frac{2}{4} \\=0.50

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

7 0
3 years ago
A bag contains yellow marbles and blue marbles, 37 in total. The number of yellow marbles is 7 more than 5 times the number of b
Mazyrski [523]

Answer:

32

Step-by-step explanation:

let b represent the number of blue marbles then

yellow = 5b + 7 and

b + 5b + 7 = 37, that is

6b + 7 = 37 ( subtract 7 from both sides )

6b = 30 ( divide both sides by 6 )

b = 5

Thus there are 5 blue and 5(5) + 7 = 25 + 7 = 32 yellow marbles

5 0
3 years ago
QUICKLY PLEASE!!<br> 18POINTS!<br> 6(3p – 2) = 24
Gekata [30.6K]

Answer:

p= 2

Step-by-step explanation:

So first you want to distribute the 6 to 3p-2 which basically means multiply

6(3p – 2) = 24

6 times 3p is 18 and 6 time -2 is -12

* remember a negative and a positive equal a negative*

18p-12=24

you want to get 18p by itself, so in order to do that you can add 12 to both sides because if you add 12 on the left side it cancels out -12 and whatever you do to one side you have to do it to the other so add 12 to 24 which is 36

18p = 36

since you want to get p by itself you divide p on both sides so it can cancel out 18 and 36/18 is 2

so p = 2

if you are wondering why i divide it and not subtract or add it is because 18 and p are stuck together so you have to divide but if it  was like 18 + p you can subtract because 18 and p arent together

6 0
3 years ago
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