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Doss [256]
3 years ago
6

Marissa wants to write an abbreviated set of directions for finding coordinates of a figure reflected across the y-axis. Which m

apping notation is correct?
(x, y) right-arrow (negative x, y)
(x, y) right-arrow (x, negative y)
(x, y) right-arrow (negative x, negative y)
(x, y) right-arrow (y, x)
Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer:

(x,y) right arrow (negative x , y)

Step-by-step explanation:

Mathematically, when we reflect a point over the x-axis; we have a result

The result is that the x- coordinate of the point reflected takes up a negative value

so what we have here is that;

(x,y) becomes (-x,y) once reflected over the y-axis

So, traditionally, we add the arrow

So our answer is thus;

(x,y) right arrow (negative x , y)

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Graph the function in the image.
il63 [147K]

Answer:

Here is the graph to the intercepts.

Step-by-step explanation:

Graph of (6, 4), (4, 3), (-2, 0)

Hope it helps :)

8 0
3 years ago
Help me out please???
xenn [34]

Answer:

(x,y) => (x+3, y+4)

Step-by-step explanation:

Given a triangle DEF, D(4,2), E(3,3), F(2,1).

Centroid of the area (and the vertices) equals the mean of the coordinates, namely ( (4+3+2)/3, (2+3+1)/3 ) = (3,2)

To translate (3,2) to (6,6), we need the rule

(x,y) => x+(6-3), y+(6-2), or

(x,y) => (x+3, y+4)

5 0
3 years ago
PLEEEEEEEEASE HELP! How the heck do i figure this out!!!?<br> Find m
Fiesta28 [93]
Here is how you find the answer. 
Do remember that the term Bisect means to cut it in half.
So here it goes.
<span>5x = 3x + 10
5x - 3x = 10
2x = 10
x = 5
Then, substitute the values, so 5*5 or 3*5+10
Then, the answer for each smaller angle is 25.
</span>Remember bisect? so 25 x 2 so the final answer is 50.
Hope this is the answer that you are looking for. Thanks for posting your question!
4 0
3 years ago
You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O
Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider  the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165)  (10,150).

Remember that  the slope-intercept form of the  linear equation is y=mx+b where m is the slope and b  is te intercept.

The slope can be calculated  by the next formula:

m=\frac{y2-y1}{x2-x1}

In this case we will assign  (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

m=\frac{150-165}{10-9} = -15

Now, we have the slope and two poitns. According to this, and taking into account that  point-slope form of the equation of a line is y-y1=m(x-x1),   find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10)   equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.  

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by  the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p   equation 2

(c) To get the cost function of the nightclub  we just have to multiply the cost of the two non-alcoholic drinks   by the number of the guests ( equation 1) and add to it  nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600  equation 3

(d) In order to find the profit in terms of the cover charge we will  subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that  the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

5 0
3 years ago
The radioactive substance cesium-137 has a half-life of
statuscvo [17]
A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.
7 0
3 years ago
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