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Andre45 [30]
3 years ago
8

Sin0=12/37 find tan0

Mathematics
1 answer:
alexira [117]3 years ago
5 0

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

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iragen [17]

Options:

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D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

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School 2 has a median of 9.

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7 0
4 years ago
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tekilochka [14]

Answer:

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Step-by-step explanation:

The sample size is calculated using the formula, n = (\frac{\sigma\times z}{\textup{Margin of error}})^2

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Given:

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thus,

a) for margin of error = $0.10

n = (\frac{\sigma\times z}{\textup{Margin of error}})^2

or

n = (\frac{0.25\times1.96}{\textup{0.10}})^2

or

n = 4.9²

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n = 24.01 ≈ 25               (Rounded off to next integer)

b) for margin of error = $0.07

n = (\frac{\sigma\times z}{\textup{Margin of error}})^2

or

n = (\frac{0.25\times1.96}{\textup{0.07}})^2

or

n = 7²

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n = 49

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n = (\frac{\sigma\times z}{\textup{Margin of error}})^2

or

n = (\frac{0.25\times1.96}{\textup{0.05}})^2

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