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quester [9]
3 years ago
4

Dunder Mifflin recently expanded its supply to include not just paper, but also copiers (much to Pam’s delight). The expansion w

as a smashing success, with the copier production process producing defective parts only 0.8% of the time during the first year. Michael Scott believes that updates to the production technology have improved this process. He randomly selects 1000 parts and finds 6 defective parts. Do these data provide evidence at the 5% level that the process has improved?
Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0
Maybe might be 6.8 but I’m not sure
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This figure shows circle Z with chords AB and RS . mAR=55° mRB=66° AB=8 m RS=8 m What is mRS?
Alina [70]
M AR = 55°
m RB = 66°
Like AB=8 m =RS →m RS = m AB

m AB = m AR + m RB
m AB = 55° + 66°
m AB = 121°

m RS = m AB
M RS = 121°

Answer: m RS is 121°
4 0
4 years ago
Read 2 more answers
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444
givi [52]

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

5 0
3 years ago
Please help me with the question below including the graph.
ehidna [41]

Answer:

13.50 ≤ 1.20x + 3

Step-by-step explanation:

Janie is saving for a CD, which costs $13.50. Janie can earn more than that amount, but needs to save at least that much to buy the CD. So, the amount of money she has needs to be greater than or equal to $13.50.

Next, Janie has $3 to begin with. Although she already has some money to start with, that is still not enough to purchase her CD. To earn money, she will do chores ($1.20 per chore). We do not know the amount of chores she will do, so we can mark that as variable x.

If we put that all together, we will get 13.50 ≤ 1.20x + 3. If you solver this equation, you can solve how many chores she will have to do, but that is not part of the question!!

Now, for the graph. A closed dot represents if it is not only greater or less than, but it also has a possibility to be equal as well. So, this dot will be closed. As I said before, the amount of money she has all together has to be greater than or equal to $13.50. Starting from the dot, you will draw the arrow to the right, which symbolizes that all of these numbers are the solution.

I hope this helped you! Have a great rest of your day.

6 0
3 years ago
A bodybuilder is 6ft 4in tall and has a body mass index of 27.6. How much does he weight?
balu736 [363]
To determine the weight of the bodybuilder and since we are given the BMI or the boddy mass index and the height, it would be best to use these values. BMI is a measurement that is used to scaled body fat based in the weight and the height of adult women and men. It is calculated by the equation as follows:

BMI = 703 (mass in lb / height in inches^2)

Given: 
height = 6ft 4in
BMI = 27.6

Solution:
height = 6 ft ( 12 in /1 ft ) + 4 in = 76 in

BMI = 703 (mass in lb / height in inches^2)
27.6 = 703 (mass in lb / 76^2)
mass = 226.77 lb or  103.08 kg
4 0
4 years ago
I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
4 years ago
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