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Vinvika [58]
2 years ago
7

3. How many 4-letter code can be formed using the first 10 letters of the English alphabet, if no letter can be repeated?

Mathematics
1 answer:
galben [10]2 years ago
7 0
Abcdefg
There cannot be more than two because there are only two vowels, e and a. But it has to be 4 lettered, which limits a lot of option, so there can only be one 4-letter code.
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Answer:

x=10

Step-by-step explanation:

2x-10=10

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Which expression simplifies to 41? Choose all that apply!
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Answer:

None of the expressions is simplified to 41.

Step-by-step explanation:

You have to follow the P.E.M.D.A.S., this is:

P:Parentheses first.

E:Exponent next.

M:Multiplication.

D:Division.

(Multiplication and Division is whichever come first, from left to right)

A: Addition.

S: Subtraction.

(Addition and Subtraction is whichever come first, from left to right).

<u><em>We are going to analyze every option:</em></u>

1. 10+ 2.4 - 1

First we have to solve the multiplication:

10+ 2.4 - 1=10+8-1

Now we have to solve the addition and subtraction from left to right:

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This is not a correct answer.

2. 10+2.(4-1)

We have to solve the parentheses first:

10+2.(4-1)=10+2.(3)

Now the multiplication and then the addition.

10+2.(3)=10+6=16\neq 41

This is not a correct answer.

3. (10+23).4-1

We have to solve the parentheses first:

(10+23).4-1=(33).4-1

Now the multiplication and then the subtraction:

(33).4-1=132-1=131\neq 41

This is not a correct option.

4. 10+(2^2.4)-1

We have to solve the parentheses first, in the parenthesis first we have to solve: 2^2 and then do the multiplication.

10+(2^2.4)-1=10+(4.4)-1=10+16-1

Now we have to solve the addition and subtraction from left to right:

10+16-1=26-1=25\neq 41

This expression is not a correct option.

Then none of the expressions is simplified to 41.

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The quotient is approximately a little more than ...

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