1/9 is equal to 0.11, and 2/9 is equal to 0.22. You can see the pattern here, if you look at the numerator of the fraction and the decimal.
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
Answer:
ABC~WXY by AA
Step-by-step explanation:
In ΔABC
∠B = 90°
∠A = 27°
To Find ∠C
Angle sum property: The sum of all angles of triangle is 180°
∠A+∠B+∠C=180°
27°+90°+∠C=180°
∠C=180°-117°
∠C=63°
In ΔWXY
∠X = 90°
∠Y = 63°
We will use angle sum property
So, ∠W+∠Y+∠X=180°
90°+63°+∠W=180°
∠W=180°-(90°+63°)
∠W=27°
So, ∠A=∠W
∠B =∠X
∠C = ∠Y
So, ABC~WXY by Angle - Angle property.
Hence ABC~WXY by AA
It would be A. <span>y = −2x − 4.
Hope this helps!!
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