All categories

2 years ago

3. How many 4-letter code can be formed using the first 10 letters of the English alphabet, if no letter can be repeated?

1 answer:

7 0

Abcdefg
There cannot be more than two because there are only two vowels, e and a. But it has to be 4 lettered, which limits a lot of option, so there can only be one 4-letter code.

You might be interested in

Simple Algebra Equation help.

Ivan

Answer:

There are 3 adult tickets and 7 child tickets

Step-by-step explanation:

You are very close.

Let x = the number of adult tickets

Let y = number of child tickets

24.95x+ 15.95y = 186.50

The total number of tickets is 10

x+y =10

Subtract y from each side

x+y-y = 10-y

x =10-y

Substitute this into the first equation

24.95x+ 15.95y = 186.50

24.95(10-y) +15.95y = 186.50

Distribute

249.5 - 24.95y +15.95y =186.5

Combine like terms

249.5 - 9y = 186.50

Subtract 249.5 from each side

249.5-249.5 - 9y = 186.50-249.5

-9y =-63

Divide each side by -9

-9y/-9 = -63/-9

y =7

Now we need to find x

x+y =10

x+7 =10

Subtract 7 from each side

x+7-7 =10-7

x =3

There are 3 adult tickets and 7 child tickets

3 0

4 years ago

Volume is measured in cubic units true false

salantis [7]

True.

<span>Volume is measured in cubic units</span>

6 0

4 years ago

Read 2 more answers

Help giving brainliest...

aksik [14]

Answer:

7, 8, 8,7,8,9

Step-by-step explanation:

brainliest plss!!<3

8 0

3 years ago

Read 2 more answers

A 2-digit number is written on a paper. What is the probability that it starts with 2?

Hatshy [7]

Answer:

1 out of 9

Step-by-step explanation:

4 0

3 years ago

The parents of three children, ages 1, 3, and 6, wish to set up a trust fund that will pay X to each child upon attainment of ag

ehidna [41]

Answer:

The equation of <em>Z</em> is: $Z=X(v^{17}+v^{15}+v^{12})+Y(v^{20}+v^{18}+v^{15})$

Step-by-step explanation:

The first child is of age 1 year.

Then the amount invested for the 1-year old is: $Xv^{17}+Yv^{20}$

The second child is of age 3 years.

Then the amount invested for the 3-year old is: $Xv^{15}+Yv^{18}$

The third child is of age 6 years.

Then the amount invested for the 6-year old is: $Xv^{12}+Yv^{15}$

The one-time investment will be:

$Z=Xv^{17}+Yv^{20}+Xv^{15}+Yv^{18}+Xv^{12}+Yv^{15}\\=X(v^{17}+v^{15}+v^{12})+Y(v^{20}+v^{18}+v^{15})$

6 0

3 years ago