It depends on the value of the discriminant of the quadratic.
If you are familiar with the quadratic formula...
x=(-b±√(b^2-4ac))/(2a)
The part under the radical sign (b^2-4ac) is called the discriminant of the quadratic (of the form ax^2+bx+c)
If the discriminant is less than zero there are no REAL solutions (however there are two imaginary solutions)
If the discriminant is equal to zero, there is just one solution
If the discriminant is greater than zero, there are two real solutions.
So depending on context, if you are to exclude imaginary solutions (which we often do) you can have 0,1, or 2 real solutions.
However you will NEVER have three solutions. (real or imaginary)
Mr. Brown can make fewer than 6 full groups to give presentations.
<h3>Inequality</h3>
Inequality is an expression used to show the non equal comparison of two or more numbers and variables.
Let x represent how many full groups Mr. Brown can make.
He wants each group to have 4 students. There are fewer than 24 students in class today, hence:
Mr. Brown can make fewer than 6 full groups to give presentations.
Find out more on inequality at: brainly.com/question/11613554
I believe it's 489 ........
Answer:
2/10
Step-by-step explanation:
First you - 20 from 40 (aka 2/10 - 4/10) and you will get 20 (aka 2/10).
