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egoroff_w [7]
3 years ago
13

Can someone plzzz help mee ill give brainlest

Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

7238.23ft Cubed

Step-by-step explanation:

To get the answer you plug the value of the radius in to the equation >

V = 4/3πr³

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What is the value of x?
AfilCa [17]

Answer:

29

Step-by-step explanation:

7 0
3 years ago
There are eight girls competing in an ice-skating competition. In how many ways can they finish in first, second, and third plac
docker41 [41]
Since we need to find the number of ways they could enter first, second and third place, (I can't demonstrate, but you should get the idea) take 8, 7 and 6 and multiply them, 5-1 we don't need, we just need 8, 7, and 6, multiply those three numbers and you get 336, there you go, 336 ways to organize all 8 girls in first, second and third place, hope this helps
7 0
3 years ago
Sarah buys a video game for $44.00 plus 4% sales tax. Her brother, Jack, buys a video game for $36.00 plus 6% tax. Show your wor
Ipatiy [6.2K]

Answer:

Sarah spent 45.76

Jack spent 38.16

Jack spent more on tax

Step-by-step explanation:

Sarahs game costs:

tax = 44 *.04 = 1.76

Total cost = game + tax

                  = 44 + 1.76

                  =45.76


Jacks game costs:

tax = 36 *.06 = 2.16

Total cost = game + tax

                  = 36 + 2.16

                  =38.16

Jack spent more on tax

4 0
3 years ago
Please help me please
dimaraw [331]

Answer:

92

Step-by-step explanation:

92+88= 180 all suplementtary angles =180

6 0
3 years ago
Read 2 more answers
Problem 1: Use the Laplace Transforms to solve:
Leokris [45]

Transforming the ODE yields

L\left\{y'' - y'\right\} = L\left\{e^{-3t}\right\}

(s^2 Y(s) - sy(0) - y'(0)) - (s Y(s) - y(0)) = \dfrac1{s+3}

(s^2 - s) Y(s) = \dfrac1{s+3}

Y(s) = \dfrac1{(s^2 - s)(s+3)} = \dfrac1{s(s-1)(s+3)}

Partial fractions:

Y(s) = \dfrac as + \dfrac b{s-1} + \dfrac c{s+3}

\implies 1 = a(s-1)(s+3) + b s(s+3) + c s(s - 1)

\implies 1 = -3 a + (2 a + 3 b - c) s + (a + b + c) s^2

\implies \begin{cases}-3a=1 \\ 2a+3b-c=0 \\ a+b+c=0\end{cases} \implies a=-\dfrac13, b=\dfrac14, c=\dfrac1{12}

\implies Y(s) = -\dfrac13 \times \dfrac1s + \dfrac14 \times \dfrac1{s-1} + \dfrac1{12} \times \dfrac1{s+3}

Take the inverse transform:

\boxed{y(t) = -\dfrac13 + \dfrac{e^t}4 + \dfrac{e^{-3t}}{12}}

3 0
2 years ago
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