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iragen [17]
3 years ago
10

Find the distance between the points (-5,7) and ( -5,-4)

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

11

Step-by-step explanation:

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The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
GuDViN [60]

Answer:106.63%.

Step-by-step explanation:To find the percentage of the price per ounce of gold increase we will use % increase formula.Therefore, the price of per ounce of gold increased by 106.63%.

7 0
2 years ago
Hellllllpppppppppp:)
andrezito [222]

Answer: No solution.

Step-by-step explanation:

These lines are parallel to each other. So, they never intersect. So, they don't have solution.

7 0
3 years ago
A company makes a profit of $7 per software program and $8 per video game. The company can produce at most 90 software programs
g100num [7]

Answer:

930 dollars

Step-by-step explanation:

Let software programs = S

Video game = V

Given that a company makes a profit of $7 per software program that is, 7S and $8 per video game that is, 8V. The company can produce at most 90 software programs and at most 80 video games per week. Since the Total production cannot exceed 120 items per week.

How many items of each kind should be produced per week in order to maximize the profit?

The to get profit P

P = 7S + 8V

Since the profit on video game is higher, we will give maximum production to video game. Therefore,

P = (30 × 7) + ( 8 × 90)

P = 210 + 720

P = 930 dollars

6 0
3 years ago
6u + 3u =18<br> simplify your answer as much as possible
tino4ka555 [31]
6u + 3u = 18
9u = 18
u = 18/9
u = 2
4 0
3 years ago
On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d
Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

                         X~ N ( 67.2 , 4.6^2 )

Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

6 0
3 years ago
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