Question

the vertices of a triangle are located at (-3,-1), (2,3),(5,2). record the triangles perimeter to the nearest whole number

Answer 1

Answer:

The perimeter of the triangle is approximately equal to 18

Step-by-step explanation:

The coordinates of the vertices of the triangle are (-3, -1), (2, 3), and (5, 2)

The formula for the lengths, l, of the sides of the triangle, given their end points coordinates is presented as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The lengths of the segments that make up the triangle are therefore;

Between the vertex points (-3, -1) and (2, 3), we have, √((-3 - 2)² + (-1 - 3)²) = √41

Between the vertex points (-3, -1) and (5, 2), we have, √((-3 - 5)² + (-1 - 2)²) = √73

Between the vertex points (2, 3) and (5, 2), we have, √((2 - 5)² + (3 - 2)²) = √10

Therefore;

The perimeter of the triangle = The sum of the lengths of the sides of the triangle =  √41 + √73 + √10

The perimeter of the triangle = √41 + √73 + √10 ≈ 18.1094

∴ The perimeter of the triangle ≈ 18, after rounding to the nearest whole number.