Write the vertex form of the equation and find the necessary coefficient to make it work.
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
Answer:
there isn;t anything posted underneath
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
Required
Divide 157 by 10 repeatedly.
This is done as follows...
157 Divided by 10 = 15 Remainder 7
15 Divided by 10 = 1 Remainder 5
1 Divided by 10 = 0 Remainder 1
<em>As per the requirement of the question, no further action or operation is required</em>
Answer: a) degree and sign
b) end behavior: left side → +∞, right side → -∞
c) x-intercepts: x = -1.3, 0.3, 1.0
<u>Step-by-step explanation:</u>
end behavior can be determined by two things:
1) the degree of the polynomial:
- if the degree is an even number, then the end behavior will be the same for both the left and right sides.
- if the degree is an odd number, then the end behavior will be different for both the left and right sides.
2) the sign of the leading coefficient:
- If the leading coefficient is positive, then the end behavior of the right side goes to positive infinity
- If the leading coefficient is negative, then the end behavior of the right side goes to negative infinity
W(x) = -5x³ + 7x - 2
Degree: 3 (odd)
Leading Coefficient: negative
So, end behavior is: right side goes to negative infinity, right side goes to positive infinity.
See attachment for x-intercepts. <em>I set the x-axis to represent tenths </em>
Answer:
C. 1.75
Step-by-step explanation:
7 paved over 4 unpaved
7 divided by 4
1.75
