Question

Astronuts in soace weigh themselves by oscillating on a spring suppose the position of an oscillating 75 kg astrounut is given by x=.32sin((pirad/s).t) where t is in s what force does the spring exerts on the astronaut at t=1.5 s

Answer 1

Answer:

F = 237 N

Explanation:

x(t) = 0.32sin(πt)

v(t) = 0.32πcos(πt)

a(t) = -0.32π²sin(πt)

a(1.5) = -0.32π²sin(π1.5) = 3.158... m/s²

F = ma = 75(3.158) = 236.870... N