I believe it is velocity. But not to sure
The
horizontal component of an angular distance can be calculated by multiplying the
distance with the cosine of the angle, Dx = D * cos θ
While
the vertical component is calculated by multiplying the distance with the sine
of the angle, Dy = D * sin θ
The
resultant displacement can then be obtained using the formula for hypotenuse
and summations of each component:
R^2
= (summation of Dx)^2 + (summation of Dy)^2
summation
of Dx = 600 * cos47 + 500 * cos128 + 300 * cos209 + 400 *
cos(-77) = -71.0372
summation of Dy = 600 * sin47
+ 500 * sin128 + 300 * sin209 + 400 * sin(-77) = 297.6267
<span> Note: you have to draw the lines to correctly
determine the angles</span>
R^2 = (-71.0372)^2 + 297.6267^2
R = 306 m
The resultant angle is:
tan θ = Dy / Dx
θ =
tan^-1 (297.6267 / -71.0372)
θ =
103˚ = [N 13˚ W]
Therefore
displacement is 306 m <span>[N 13˚ W].</span>
Initial velocity U = 0
Final velocity V = 32.23 m/s
Explanation:
Given that a coin is dropped from the top of the Tower of Pisa, 53m above the ground.
What is the coin's initial velocity ?
Since the coin is dropped from the tower, the initial velocity U will be equal to zero.
Therefore, U = 0
But the final velocity V will be calculated by using the formula
V^2 = U^2 + 2gH
V^2 = 0 + 2 × 9.8 × 53
V^2 = 1038.8
V = sqrt ( 1038.8)
V = 32.23 m/s
sorry if did not help :(
<span>There is no special name for that. Physics is usually just concerned with "forces", and doesn't specify whether the force pushes or pulls. If you want to be more specific, you can just call it a "pulling force".
I hoped this was satisfying!:)</span>
Answer:
the answers are the first and last option