Question

When the current in one coil changes at a rate of 5.0 A/s, an emf of −4.0 ✕ 10−3 V is induced in a second, nearby coil. What is the mutual inductance of the two coils (in H)?

Answer 1

Answer:

$M = 8 \times 10^{-4} H$

Explanation:

As per the condition of mutual inductance of the coil we know that flux linked with coil 2 is proportional to the current in the coil 1

so here we will have

$\phi_2 = M i_1$

here we know that rate of change in flux is equal to the EMF induced in the coil

so we will have

$\frac{d\phi_2}{dt} = M \frac{di_1}{dt}$

so we have

$EMF = M \frac{di}{dt}$

now plug in all values in it

$4 \times 10^{-3} = M (5)$

$M = 8 \times 10^{-4} H$