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2 years ago

Can someone please help me please

Mathematics

1 answer:

Anarel [89]2 years ago

3 0

Answer:

it's answer is C. 12/10 = 4 / x

Step-by-step explanation:

As the triangles are similar so

4/12 = x/10

Or cross multiply then

12/10 = 4/x

Hope it will help :)

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3 years ago

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Need help ASAP thanks

Otrada [13]

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3 years ago

Which would not be a step in solving 5x + 15 + 2x = 24 + 4x?

Klio2033 [76]

Answer:

A. Use the distributive property.

Step-by-step explanation:

We cannot use the distribute property because there are not parentheses to distribute a number through.

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3 years ago

Can anyone help me answer this?

netineya [11]

We need to know how much tax she must pay based on her taxable income ,
Since un the table it states that taxable incomes that range between $0-$132000have a tax rate of 18% of each $1 .
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Hence we know how much tax she must pay .
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Hope you found this helpful , good luck !

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3 years ago

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If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

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2 years ago