Answer:
V CH4(g) = 190.6 L
Explanation:
assuming ideal gas:
∴ STP: T =298 K and P = 1 atm
∴ R = 0.082 atm.L/K.mol
∴ moles (n) = 7.80 mol CH4(g)
∴ Volume CH4(g) = ?
⇒ V = RTn/P
⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)
⇒ V CH4(g) = 190.6 L
The balanced chemical reaction is:
N2 + 3H2 = 2NH3
We are given the amount of hydrogen gas to be used in the reaction. This will be the starting point of the calculations.
24.0 mol H2 (2 mol NH3 / 3 mol H2 ) = 16 mol NH3
Therefore, ammonia produced from the reaction given is 16 moles.
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Molar mass of 
<u>As we know</u>–
1 mol =
formula units
1 mol = 143.092 g = formula units
Henceforth –
formula units –
The correct answer is C, as if you do not understand something, it's always best to ask for help, especially when performing a sensitive procedure.
The moles of O2 are needed to react completely with 1.00 mol of C₂H₂ is 5 mol , 0.23 moles of C₂H₂ are needed to form 0.46 mol of CO₂ .
<h3>What is a Balanced Reaction ?</h3>
A balanced reaction is a reaction in which the number of atoms present in the reactants is equal to the number of atoms in the products.
It is given in the question that
the combustion of Acetylene is given by
2 H―C≡C―H + 5 O₂ → 4 CO₂ + 2 H₂O
Given moles of Acetylene = 1 mol
Moles of oxygen needed = 5 mol
as the mole fraction of Acetylene to Oxygen is 1 :5
The mole of Acetylene needed to form 0.46 mol of CO₂ is ?
mole fraction of CO₂ to Acetylene is 4:2
Therefore 0.23 moles of CO₂ is required.
To know more about Balanced Reaction
brainly.com/question/14280002
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