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Gre4nikov [31]
3 years ago
8

Purple Group Header Warm-Up Why can I smell a chocolate bar even though it is a solid? Read the description of the office myster

y and write your prediction below. On a warm afternoon, a Universal Space Agency office worker returned from lunch break and noticed the office smelled like chocolate. She didn't see anything in the air, but she noticed her coworker was opening the wrapper of a solid bar of chocolate. Why can the office worker smell the chocolate bar even though it is in solid form?
Chemistry
1 answer:
likoan [24]3 years ago
4 0

Answer:

The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas

Explanation:

There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.

These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.

For example, 3 methylbutanal, vanillin, and several organic compounds which are known to be readily volatile.

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Answer:

Lines of latitude run from east to west.

Explanation:

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2 years ago
Calculate the concentration in % (m/m) of a solution containing 30.0g of mgcl2 dissolved in 270.0g of h20
qaws [65]
As the question tells you, you need to use the formula

% mass= mass of solute/ mass of solution x 100

mass solute= 30.0 g
mass of solution= 30.0 + 270.0= 300.0 g

% mass= 30.0/ 300.0 x 100= 10%

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2 years ago
Indicate what happens to the concentration of Pb2+ in each half cell
Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

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3 years ago
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bezimeni [28]

Answer: Option (B) is the correct answer.

Explanation:

As the given reaction is as follows.

               CO_{2}(g) + C(graphite) \rightarrow 2CO(g)

Equilibrium constant for this reaction will be as follows.

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According to Le Chatelier's principle, when we increase the temperature then the equilibrium will shift towards the right hand side.

As a result, concentration of carbon dioxide will decrease whereas concentration of carbon monoxide will increase.

Thus, we can conclude that in the given reaction equilibrium constant for this reaction will decrease with increasing temperature.

 

8 0
3 years ago
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