All categories

1 year ago

11. You have 700 grams of AgO. How many moles are present?

Chemistry

1 answer:

solniwko [45]1 year ago

7 0

<h2>Answer:</h2>

5.65moles

<h2>Explanations:</h2>

The formula for calculating the number of moles the compound contain is given as:

$moles=\frac{Mass}{Molar\text{ mass}}$

Given the following parameters

Mass of Ag = 700grams

Determine the molar mass of AgO

Molar mass = 107.87 + 16

Molar mass = 123.87g/mol

Determine the moles of AgO

$\begin{gathered} moles=\frac{700}{123.87} \\ moles\text{ of AgO}=5.65moles \end{gathered}$

Hence the moles of AgO present is 5.65moles

You might be interested in

How much heat is evolved in converting 1.00 mol of steam at 155.0 ∘c to ice at -50.0 ∘c? the heat capacity of steam is 2.01 j/(g

Ne4ueva [31]

When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three phases changes from steam to liquid and from liquid to ice (solid) :

when Q = M*C*ΔT

Q is the heat in J

and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g

C is the specific heat J/g.°C

ΔT is the change in temperature

Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice * ΔT ice)]

= 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]

∴Q = 7444.8 J

and when we know that the heat of fusion for water = 334J/g

and heat of vaporization for water = 2260J/g

∴Q for the two phases changes = M * (2260+334)

= 18 * (2260+334)

= 46692 J

∴ Q total = 7444.8 + 46692 = 54136.8 J

5 0

3 years ago

an unknown molecule is found to consist of 24.2% carbon by mass, 4.0% hydrogen by mass and the remaining mass is due to chlorine

Paha777 [63]

Answer:

C3 H6 Cl 3

Explanation:

C -24.2%

H - 4.0%

Cl - (100-24.2 - 4.0)=73.8 %

We can take 100g of the substance, then we have

C -24.2 g

H - 4.0 g

Cl - 73.8 g

Find the moles of these elements

C -24.2 g/12.0 g/mol =2.0 mol

H - 4.0 g/1.0 g/mol = 4. 0 mol

Cl - 73.8 g/ 35.5 g/mol = 2.1 mol

Ratio of these elements gives simplest formula of the substance

C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1

CH2Cl

Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol

Real molar mass = 150 g/mol

real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3

So, Real formula should be C3 H6 Cl 3.

4 0

3 years ago

Read 2 more answers

Why is it difficult to accurately represent ammonia and methane on paper?

andrew-mc [135]

Answer:

The correct answer is because the molecular structure.

Explanation:

The difficulty of ammonia and methane to be represented on paper is due to the molecular structure. These compounds have a three-dimensional projection with defined angles. Ammonia presents angles of 109.5º between the atom of Nitrogen and those of Oxygen. The ammonia presents 107.8º between the oxygen atoms.

In the methane molecule, there is 109.5º between the hydrogen molecules and the carbon atom. This results in the need for a 3D representation of the molecule.

Have a nice day!

6 0

3 years ago

13. Which statement about trace elements in our atmosphere is false?

tatiyna

Answer: sorry I’m not sure

Odjri:

6 0

3 years ago

sulfate = SO4 -2 phosphate = PO4 -3 hydroxide = OH- sodium hydroxide aNa(OH)2 bNa(OH)3 cNa2OH 4NaOH

blsea [12.9K]

4. NaOH
____________________________________

6 0

3 years ago