Remembering the equation Q=MCdeltaT where
q=is the amount of heat energy
M=mass
C=specific heat
deltaT= change in temperature
Therefore, using the equation we can substitute values and solve for q.
Q= (15 grams) (0.129 J/(gx°C))(85-22)
Q=(15) ((0.129 J/(gx°C)) (63)
Q=121.9 Joules
The energy needed to raise the temperature of 15 grams of gold from 22 degrees Celsius to 85 degrees Celsius is then 121.9 Joules or 122 Joules (if rounded up).
Answer:
The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet. Although the purple toy is now closer to the magnet, it is still pretty far and will have a somewhat big potential energy when traveling to the magnet.
Explanation:
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Answer:
4.36 g of Carbon
Solution:
Step 1: Calculate the %age of Carbon in given Solid as;
Mass of Carbon = 35.8 g
Mass of Hydrogen = 3.72
Total Mass = 35.8 g + 3.72 = 39.52 g
%age of Carbon = (35.8 g ÷ 39.52 g) × 100
%age of carbon = 90.58 %
Step 2: Calculate grams of Carbon in 4.82 g of given solid as;
Mass of Carbon = 4.82 g × (90.58 ÷ 100)
Mass of Carbon = 4.36 g
Answer:
105
Explanation:
Density = mass/volume
therefore volume = mass/density
826/7.9=105 (To three significant figure)
