Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4
Answer:The crystal structures of five 6-mercaptopurine derivatives, viz. 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(3-methoxyphenyl)ethan-1-one (1), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-methoxyphenyl)ethan-1-one (2), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-chlorophenyl)ethan-1-one (3), C15H11ClN4O2S, 2-[(9-acetyl-9H-purin-6-yl)sulfanyl]-1-(4-bromophenyl)ethan-1-one (4), C15H11BrN4O2S, and 1-(3-methoxyphenyl)-2-[(9H-purin-6-yl)sulfanyl]ethan-1-one (5), C14H12N4O2S. Compounds (2), (3) and (4) are isomorphous and accordingly their molecular and supramolecular structures are similar. An analysis of the dihedral angles between the purine and exocyclic phenyl rings show that the molecules of (1) and (5) are essentially planar but that in the case of the three isomorphous compounds (2), (3) and (4), these rings are twisted by a dihedral angle of approximately 38°. With the exception of (1) all molecules are linked by weak C—H⋯O hydrogen bonds in their crystals. There is π–π stacking in all compounds. A Cambridge Structural Database search revealed the existence of 11 deposited compounds containing the 1-phenyl-2-sulfanylethanone scaffold; of these, only eight have a cyclic ring as substituent, the majority of these being heterocycles.
Keywords: crystal structure, mercaptopurines, supramolecular structure
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Chemical context
Purines, purine nucleosides and their analogs, are nitrogen-containing heterocycles ubiquitous in nature and present in biological systems like man, plants and marine organisms (Legraverend, 2008 ▸). These types of heterocycles take part of the core structure of guanine and adenine in nucleic acids (DNA and RNA) being involved in diverse in vivo catabolic and anabolic metabolic pathways.
6-Mercaptopurine is a water insoluble purine analogue, which attracted attention due to its antitumor and immunosuppressive properties. The drug is used, among others, in the treatment of rheumathologic disorders, cancer and prevent
Step-by-step explanation:
Answer:
65 degrees.
Step-by-step explanation:
Since angle JLG is 115 degrees, andgle JLH must be 65 because the two angles are supplementary, which means they add up to 180 degrees.
Answer:
8. 504ft²
9. 4970yd² (rounded to 3 s.f.)
Formulas (For easy reference):
Area of rectangle = length × breadth
Area of circle = pi×r×r
Circumference of circle = pi×r×2
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Step-by-step explanation:
8. You know a box has 6 sides, and there are 3 types of surfaces that are different from each other, and you have to multiply each side by 2 cus there are the front and backside (You can draw the box with its dimensions to see the 3 types of surfaces and why I multiplied by 2):
(2×12×6) + (2×12×10) + (2×6×10) = 144 + 240 + 120
= 504ft²
9. The net of a cylinder contains two circles of radius 24yd and one long sheet to wrap around the circles with the length that is the circumference of the circle (so that it can wrap around the two circles) and a width which is the height of the cylinder (9yd).
2 Circles = 2×pi×24×24
= 1152pi
Long sheet = 9×24×2×pi
= 432pi
Now we can add all of them together:
432pi+1152pi = 1584pi
= 4970yd² (rounded to 3 s.f.)
