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Alchen [17]
3 years ago
6

energy is transferred between the atmosphere and hydrosphere by which two processes A. evaporation and runoff B.precipitation an

d evaporation C. condensation and evaporation D. runoff and condensation
Chemistry
1 answer:
Makovka662 [10]3 years ago
4 0
I believe it is c. hope this helps.
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What is the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make
Elena L [17]

Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Explanation:

Given: Volume of solute = 120 mL

Volume of solvent = 350 mL

Now, total volume of the solution is as follows.

V_{total} = V_{solute} + V_{solvent}\\= 120 mL + 350 mL\\= 470 mL

Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.

\frac{V_{solute}}{V_{total}} \times 100 mL\\\frac{120 mL}{470} \times 100 mL\\= 25.53 mL

Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.

Percent (v/v) = \frac{25.53 mL}{100 mL}\\= 25.5%

Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

7 0
3 years ago
Which compound is produced by a neutralization?
olchik [2.2K]

Explanation:

HNO3(aq) is the compound produced by a neutralization

6 0
3 years ago
A city council is putting together its conservation policy. Part of the policy deals with the production of electricity for the
Musya8 [376]

Answer:

D

Explanation:

a city would first need to know the cost and benefits

7 0
4 years ago
How to calculate calories
Airida [17]

Answer:If you are sedentary (little or no exercise) : Calorie-Calculation = BMR x 1.2.

If you are lightly active (light exercise/sports 1-3 days/week) : Calorie-Calculation = BMR x 1.375.

Explanation:

8 0
3 years ago
If it requires 23.4 milliliters of 0.65 molar barium hydroxide to neutralize 42.5 milliliters of nitric acid, solve for the mola
rodikova [14]
Volume Ba(OH)2 = 23.4 mL in liters : 

23.4 / 1000 => 0.0234 L

Molarity  Ba(OH)2 = 0.65 M

Volume HNO3 = 42.5 mL in liters:

42.5 / 1000 => 0.0425 L

number of moles Ba(OH)2 :

n = M x V

n = 0.65 x 0.0234 

n = 0.01521 moles of Ba(OH)2

Mole ratio :

<span>Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O
</span>
1 mole Ba(OH)2 ---------------- 2 moles HNO3
 0.01521 moles ----------------- moles HNO3

moles HNO3 = 0.01521 x 2 / 1

moles HNO3 = 0.03042 / 1

= 0.03042 moles HNO3

Therefore:

M ( HNO3 ) = n / volume ( HNO3 )

M ( HNO3 ) =  0.03042 / 0.0425

M ( HNO3 ) = 0.715 M

5 0
3 years ago
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