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PolarNik [594]
4 years ago
14

1.What is the amount of energy required to raise the temperature of 150 grams of aluminum by 10°C?

Chemistry
1 answer:
Wittaler [7]4 years ago
8 0
1. i believe its A im not sure tho

2 im think its true

3 C

4 B
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A) What volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution?
azamat

Answer:

A.0.51L

B 1.67L

Explanation:

using the formula ;C1V1 =C2V2

15.8×V1=2×4

15.8V1=8

V1=8/15.8

V1=0.51L

apply the same method for B

4 0
2 years ago
Which of the following is NOT considered a branch of Chemistry?
mestny [16]

Answer:

Pure Chemistry -- is NOT considered a branch of Chemistry.

Explanation:

Second question is number 4.

4 0
3 years ago
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PLEASE HELP. What volume of 0.050 M of KOH neutralizes 200. mL of 0.0100 M HNO3?
dangina [55]
I think it’s B .. not sure
5 0
3 years ago
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estructura lewis del Sulfuro de potasio (K2S) y la del óxido de boro (B2O3). Ayuda es urgente porfaaaaaaaaa!!!
N76 [4]

Answer:

ok

Explanation:

you want me to figure this out in that language into english ok

4 0
3 years ago
Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 32.4 g of carbon and 37
Gnoma [55]

Answer:

The answer to your question is:

Explanation:

Law of constant composition states that a given compound always contains its component elements in a fixed ratio.

Data

Sample 1   32.4 g of C and 373 g of Cl

Sample 2  12.3 g of C and 112 g of Cl

Convert the grams to moles and compare the ratios

Sample 1                                             Sample 2

          12 g of C --------------- 1 mol                        12 g of C --------------  1 mol

          32.4 g    ----------------  x                              12.3         -------------   x

          x = (32.4 x 1) / 12                                        x = (12.3 x 1) / 12

          x = 2.7 moles of C                                     x = 1.025 moles of C

          35.5 g of Cl ----------   1 mol                       35.5 g of Cl ----------  1 mol

          373 g  ------------------    x                             112 g of Cl   -----------  x

         x = (373 x 1) / 35.5                                       x = (112 x 1) / 35.5

         x = 10.5 moles of Cl                                    x = 3.15 moles of Cl

Ratio

        10.5 / 2.7 = 3.9                                             3.15/1.025 = 3.1

The ratio must be equal in both samples to say that the law is constant. So the answer is NO.

2.-

1) H3PO4                           3 hydrogens

2) Na2HPO4                     1 hydrogen

3) Ca(HCO3)2                   2 hydrogens

4) Ba(C2H3O2)2               6 hydrogens

                           

8 0
3 years ago
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