All categories

3 years ago

Which compound is produced by a neutralization?

Chemistry

1 answer:

olchik [2.2K]3 years ago

6 0

Explanation:

HNO3(aq) is the compound produced by a neutralization

You might be interested in

Mrs. J’s feet are aching at the end of a long day. At home, she dissolves 26.0 g of Epsom salt, MgSO4, in 1.5 kg of water. What

notka56 [123]

Answer:

-3 °C

Explanation:

adding salt lowers the freezing point of the water

6 0

3 years ago

How do you solve (2x+1)+(x-10)=90

Tamiku [17]

Start by adding ten to 90 then subtract ING one

4 0

3 years ago

How does the structure of a saturated fatty acid differ from an unsaturated fatty acid? Based on its structure, how does an unsa

Sonbull [250]

Answer:

unsaturated fatty acid are liquid in nature, posses multiple bond in it's structure where as saturated fatty acid are solid in nature, have only single bonds in it's structure.

7 0

3 years ago

The energy of any one-electron species in its nth state (n = principal quantum number) is given by E = –BZ2 /n2 where Z is the c

Ivahew [28]

Explanation:

(a) The given data is as follows.

B = $2.180 \times 10^{-18} J$

Z = 4 for Be

Now, for the first excited state $n_{f}$ = 2; and $n_{i} = \infinity$ if it is ionized.

Therefore, ionization energy will be calculated as follows.

I.E = $\frac{-Bz^{2}}{\infinity^{2}} - (\frac{-2.180 \times 10^{-18} J /times (4)^{2}}{(2)^{2}})$

= $8.72 \times 10^{-18} J$

Converting this energy into kJ/mol as follows.

$8.72 \times 10^{-18} J \times 6.02 \times 10^{23} mol$

= 5249 kJ/mol

Therefore, the ionization energy of the $Be^{3+}$ ion in its first excited state in kilojoules per mole is 5249 kJ/mol.

(b) Change in ionization energy is as follows.

$\Delta E = -Bz^{2}(\frac{1}{(4)^{2}} - {1}{(2)^{2}}) = \frac{hc}{\lambda}$

$\frac{hc}{\lambda} = 0.1875 \times 2.180 \times 10^{-18} J \times (4)^{2}$

$\lambda = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^{8} m/s}{0.1875 \times 2.180 \times 10^{-18} J \times 16}$

= $303.7 \times 10^{-10} m$

or, = $303.7^{o}A$

Therefore, wavelength of light given off from the $Be^{3+}$ ion by electrons dropping from the fourth (n = 4) to the second (n = 2) energy levels $303.7^{o}A$ .

5 0

3 years ago

NF3 Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. +- CHONS

hram777 [196]

Here is the correct question.

Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.

NF3

SBr2

CCl4

Answer:

Explanation:

The objective here is to draw the molecule three molecules by placing atoms on the grids and connecting them with their respective bonds, therefore including all the lone pairs of electrons.

See the attachment below for the diagrams.

The first compound is know as Nitrogentrifluoride. A non-flammable greenhouse gas. It is majorly used for he production of semi conductors. It has a trigonal planar structure.

SBr2: Sulfur dibromide is a yellowish liquid toxic gas. It results as a reaction between SCl_2 and HBr. Its has a Bent Structure.

CCl_4 : carbon tetrachloride has the presence of a colourless liquid with a sweet smell. Carbon tetrachloride is used for different domestic uses such as: cleaning surfaces, fumigating, cleaning metals etc. It has a tetrahedral structure.

8 0

3 years ago