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VikaD [51]
3 years ago
10

In which of the following processes will delta S be negative? Select one from above

Chemistry
1 answer:
Alona [7]3 years ago
3 0

Answer:

CO2 (s) -->Co2 (g) will be the answer

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What is the density of an object if its mass is 10 g and a volume of 2 mL?
Lilit [14]

Hi there! Let's solve this problem shall we!

⠀Volume = 10g

      Mass = 2 mL

In this specific problem, they are asking us to find the <u><em>density </em></u>of the object. So,<u><em> using the information given to us</em></u> (volume and mass), let's solve the problem!

Now, if you remember, D = M ÷ V

So, let's fill in the blanks!

D = Our unknown value

M = 2mL

V = 10g

Here is the filled out formula:

D = M ÷ V

D = 2mL ÷ 10g

D = 5 g/mL

*Make sure you put the units for your final solution!*

4 0
1 year ago
Since the number of atoms in a substance is so large , a unit to count them was created. This unit is the number of atoms in 12
larisa86 [58]

The number of atoms in one mole of any substance is measured by Avogadro's number. The value of Avogadro's number is 6.023 x 10 ^23. It is named after scientist Avogadro who proposed this number. 12 grams of carbon-12 represents 1 mole of carbon-12. For this reason, the number of atoms present in 1 mole of any substance is 6.023 x 10 ^23. Therefore, the number of atoms present in 1 mole carbon-12 is 6.023 x 10^23.


(Answer) This unit is the number of atoms in 12 grams of carbon-12 and known as Avogadro's number.

7 0
3 years ago
Organisms such as grass and lichens are classified as
mash [69]

I think the answer is producers

I hope that helped and have a nice day!! (:

3 0
3 years ago
Why is green light cool
shepuryov [24]

Because

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4 0
3 years ago
Read 2 more answers
An archer pulls her bowstring back 0.370 m by exerting a force that increases uniformly from zero to 264 N. (a) What is the equi
Arte-miy333 [17]

Answer:

713.51 N/m

Explanation:

Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.

From hook's law,

F = ke ...........................Equation 1

Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.

Make k the subject of the equation,

k = F/e ............................ Equation 2

Given: F = 264 N, e = 0.37 m.

Substitute into equation 2

k = 264/0.37

k = 713.51 N/m

Hence the spring constant of the bow  = 713.51 N/m

3 0
3 years ago
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