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DiKsa [7]
3 years ago
9

How many atoms are in 3.14 mol of H2O

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0
Here is the answer 3.783 x 10^24.
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the reaction of two gases in a sealed container produces a different gas and the system reaches equilibrium. what change in conc
telo118 [61]

Answer: Increasing the concentration of a reactant or decreasing the concentration of the product.

Explanation: For the equilibrium of the reaction to shift to the left, we must decrease the concentration of a reactant or increase the concentration of the product. This is based on Le Chatelier's principle which describes the effect on the equilibrium of changes in concentration or pressure of a product or a reactant. Adding more products in a system would disturb the equilibrium thus it would cause to reestablish it by shifting the reaction to the left producing the reactants. This would also be the same when you decrease the number of reactants in the system.

5 0
3 years ago
What is an organic chemical?
andriy [413]

Answer:

B is correct answer ...

8 0
4 years ago
If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to
Over [174]

Answer:

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

5 0
3 years ago
Read 2 more answers
How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium
Pepsi [2]

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as \text{Pb}^{2+} ions. The formula for a nitrate ion is {\text{NO}_3}^{-}. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each \text{Pb}^{2+} ion in lead nitrate would pair up with two {\text{NO}_3}^{-} ions. The formula for lead nitrate will be \text{Pb}({\text{NO}_3})_2. Each formula unit of lead nitrate will contain one \text{Pb}^{2+} ion and two {\text{NO}_3}^{-} ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as \text{Cr}^{3+}. Similarly, each \text{Cr}^{3+} will pair up with three {\text{NO}_3}^{-} ions. The formula for chromium (III) nitrate will be \text{Cr}(\text{NO}_3})_3. Each formula unit of chromium (III) nitrate will contain one {\text{NO}_3}^{-} ion and three {\text{NO}_3}^{-} ions.

0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of {\text{NO}_3}^{-} ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.

7 0
4 years ago
Could someone help pls ​
drek231 [11]
<h3>Solution-:</h3>

  • option D
  • maintains a constant volume.

#<em>o</em><em>f</em><em>f</em><em>i</em><em>c</em><em>a</em><em>i</em><em>l</em><em> </em><em>Nazo</em>

<em>ll </em><em>Radhe</em><em> Radhe</em><em> ll</em>

4 0
3 years ago
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