Answer:
0,2,8,3
Explanation:
k shell takes 2,L shell takes 8 and M shell takes the remaining which is 3
That is true, the potential energy they possessed at the airplane door would be converted to kinetic energy. And if they driver is high up, he has further to fall. As the skydivers jump, the energy would be converted to kinetic energy.
Answer:
The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:
pOH= -log [OH⁻]
In this case, pOH has a value of 2.7. Replacing:
2.7= -log [OH⁻]
and solving:
[OH⁻]=10⁻² ⁷
you get:
[OH⁻]≅ 2*10⁻³
<u><em>The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³</em></u>
Answer: The correct option is B.
Explanation: This is an example of radioactive decay and all the radioactive decay processes follow First order of kinetics.
Expression for the half life of first order kinetics is:
We are given:
Putting in above equation, we get:
Expression to calculate the amount of sample which is unchanged is:
where,
N = Amount left after time t
= Initial amount
k = Rate constant
t = time period
Putting value of k = 0.05625 and t = 24.6 in above equation, we get:
The above fraction is the amount of sample unchanged and that is equal to 
Hence, the correct option is B.
E=MC(delta)T
=20.0g x 9.00J/g x (94.4-22.8) C
= 12,924.0 J
