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3 years ago

Please, someone, help me ASAP

Mathematics

1 answer:

ryzh [129]3 years ago

4 0

1.) Beachy-Keen
2.) shorething
3.) shorething
4.) Beachy-Keen
5.) shorething

let me know if you think any of these are incorrect hope it helps

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The speed of a ship is given by d3, where d is the distance the ship travels in 3 hours. if the ship travels 48 miles in 3 hours

Kay [80]

Hello there! Thank you for asking your question here at Brainly! I will be assisting you today with answering this problem, and will teach you how to handle it on your own in the future.

First, let's take a look at our problem.
"The speed of a ship is given by D3, where D is the distance the ship travels in 3 hours. If the ship travels 48 miles in 3 hours, what is the speed of the ship?"

To solve for this, we need to understand the formula for speed.
The formula for speed is:
Speed = $\frac{Distance}{Time}$

Now that we have our formula, let's define our variables.

So, we have our distance, 48 miles, and our time, 3 hours.
Let's plug in these numbers to the formula.
Speed = $\frac{48}{3}$

Simplify the fraction to get the speed.
$\frac{48}{3}$ = 16.

Your final equation is:
Speed = 16.

Our final answer is 16 mph.

I hope this helps!

4 0

4 years ago

Read 2 more answers

The population of a certain species of insect is given by a differentiable function P, where P(t) is the number of insects in th

Step2247 [10]

Answer:

$\frac{dP}{dt} \ =\ \frac{1}{5}P$

Step-by-step explanation:

Given

Variation: Directly Proportional

Insects = 10 million when Rate = 2 million

i.e. $P = 10\ million$ when $\frac{dP}{dt} = 2\ million$

Required

Determine the differential equation for the scenario

The variation can be represented as:

$\frac{dP}{dt} \ \alpha\ P$

Which means that the rate at which the insects increase with time is directly proportional to the number of insects

Convert to equation

$\frac{dP}{dt} \ =\ k * P$

$\frac{dP}{dt} \ =\ kP$

Substitute values for $\frac{dP}{dt}$ and P

$2\ million = k * 10\ million$

Make k the subject

$k = \frac{2\ million}{10\ million}$

$k = \frac{2}{10}$

$k = \frac{1}{5}$

Substitute $\frac{1}{5}$ for k in $\frac{dP}{dt} \ =\ k * P$

$\frac{dP}{dt} \ =\ \frac{1}{5}* P$

$\frac{dP}{dt} \ =\ \frac{1}{5}P$

8 0

3 years ago

What is the midpoint of the segment joining the points (4, -2) and (-8, 6)? A. (6,4)

kvasek [131]

$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -8 + 4}{2}~~~ ,~~~ \cfrac{ 6 -2}{2} \right)\implies \left( \cfrac{-4}{2}~~,~~\cfrac{4}{2} \right)\implies (-2~~,~~2)$