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ladessa [460]
3 years ago
11

1. A researcher would like to compare the effectiveness of video versus reading for communicating information to adolescents. A

sample of n1= 10 adolescents is given a pamphlet explaining nuclear energy and told that they will be tested on the information. A separate sample of n2= 10 adolescents is shown a video that contains the same information presented in a fast-paced visual form and told that they will be tested. One week later all 20 subjects are given a test on nuclear energy. The average score for the pamphlet group was 1= 51 with s12= 16. The video group averaged 2= 46 with s22= 20. Conduct a t-Test (two-tail, α = .05) for two Independent groups to see if there is a significant difference between the two groups (follow the Handout).
Mathematics
1 answer:
Bingel [31]3 years ago
7 0

Answer:

There is significant statistical evidence to suggest there is a difference between the groups

Step-by-step explanation:

The number of adolescents in the sample that were given a pamphlet, n₁ = 10

The average score of those given a pamphlet, \bar x_1 = 51

s₁² = 16

The number of adolescents in the sample that were given a video, n₂ = 10

The average score of those given a video, \bar x_2 = 46

s₂² = 20

The alpha level of the test, α = 0.05

H₀ = No difference

Hₐ = Difference between the groups

The test statistic for the difference in mean is given as follows;

t=\dfrac{(\bar{x}_1-\bar{x}_{2})}{\sqrt{\dfrac{s_{p}^{2} }{n_{1}}+\dfrac{s _{p}^{2}}{n_{2}}}}

Plugging in the values, gives;

t=\dfrac{(46-55)}{\sqrt{\dfrac{18 }{10}+\dfrac{18}{10}}}  \approx -4.73

The degrees of freedom, n₁ + n₂ - 2 = 20 - 2 = 18

The critical-t = 2.101

Therefore

Given that the test statistic is larger than than the critical-t, we reject the null hypothesis that there is no difference

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Answer:

2.  3.913 kg (3 dp)

3.  light cream

4.  240 CoffeeStops

5.  7 CoffeeStops per square mile

6.  2,861 cups of coffee each day

Step-by-step explanation:

Given:

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  • Light cream density at 20 °C = 1.012 kg/l
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<u>Question 2</u>

\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

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<u>Question 3</u>

Given:

  • Volume of liquid = 9 liters
  • Mass of liquid = 9.108 kg

\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

<u>Question 4</u>

Given:

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\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}

Therefore, there are 240 CoffeeStops.

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<u>Question 5</u>

Given

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\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

<u>Question 6</u>

Given:

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\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}

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Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

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