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anygoal [31]
3 years ago
7

What is the answer to 8x - 4 = 7x - 1

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0
8x-7x=-1+4
1x/1 =3/1
x=3


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Given that (8,4) is on the graph of f(x), find the corresponding point for the function f(4x).
LekaFEV [45]
\bf \stackrel{f(x)}{(8~~,~~4)}\qquad \qquad \qquad \stackrel{f(4x)}{(4(8)~~,~~4)}\implies (32,4)
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3 years ago
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Use the zero product property to find the solutions to the equation x^2+x-30=12
lukranit [14]

Answer:

Due to there being no negatives in this equation, you can pretty much just eliminate the first 3 answers.


However in working out, here is what I did.

x^2 + x - 30 = 12 (+30) 

= x^2 + x = 42


Then you can conclude that the answer is D, due to 6 x 6 = 36, plus 7 equaling 42. 





8 0
3 years ago
I’ll give brainliest!!!
Maslowich

14a. =

15b. 2/3 is less than 0.667

16c. 3 7/8 is greater than 3.375

17d. 3/8 is less than 1/2

6 0
3 years ago
A cone has a height of 1 meter and a diameter of 2 meters. What is it’s volume
Ber [7]

Cone volume formula: V = πr²h/3

r = radius

h = height

The radius is half the diameter, so, we can divide.

2 / 2 = 1

Now, solve with the given values.

V = π(1)²(1)/3

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6 0
4 years ago
An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

b) The approximate probability that at least 9 carry the gene is:

P(x\geq9)=1-P(x\leq 8)\\\\\\

P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\

P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021

8 0
3 years ago
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