Let
, so that
and
. The integral is then equivalent to
Answer:
5) there are different ways 30 ways
6) What will most likely happen is that it will land anywhere but for it to land on 3 again is a small chance
Step-by-step explanation:
Based on this sample, 100 toys will not meet standards.
There is 1 value that is 75 or lower in this simulation. This makes the experimental probability 1/10. 1/10(1000) = 100 toys for the month.
a) We know that the probability Jane will win is 0.2, and draws is 0.3, which leaves the probability of her losing to be 0.5 (1 - 0.2 - 0.3 = 0.5).
I'll begin by filling in for the first game:
win = 0.2, draw = 0.3, lose = 0.5
Next, we'll fill in for if she wins, draws, or loses the second game. The probabilities would be the same as the first game for the second game.
Win (0.2): win = 0.2, draw = 0.3, lose = 0.5
Draw (0.3): win = 0.2, draw = 0.3, lose = 0.5
Lose (0.5): win = 0.2, draw = 0.3, lose = 0.5
b) To find the probability that Jane will win both games, we need to multiply the probability of Jane winning the first game by the probability of her winning the second game.
0.2 x 0.2 = 0.04
Hope this helps! :)
