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3 years ago

0=-2y+10-6x 14-22y=18x

Mathematics

1 answer:

Inessa05 [86]3 years ago

5 0

Answer:

x=2,y=−1

Step-by-step explanation:

Solve for y in the first equation.

y=−9x/11+7/11

0=−2y+10−6x

Replace all occurrences of y with −9x/11+7/11 in each equation.

0=−48(x−2)11

y=−9x11+711

Solve for x in the first equation.

x=2

y=−9x/11+7/11

Replace all occurrences of x with 2 in each equation.

y=−1

x=2

The solution to the system is the complete set of ordered pairs that are valid solutions.

(2,−1)

The result can be shown in multiple forms.

Point Form:

(2,−1)

Equation Form:

x=2,y=−1

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Two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube. One particle tra

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This shows that it will take the particle 23 secs to meet.

The distance travelled by each particle is 50cm

If two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube,

The first particle distances are 97cm, 93cm, 89cm... every 2secs

This form an arithmetic sequence and the nth term is expressed as:

Tn = a + (n - 1)d

a is the first term = 97

d is the common difference = 4

Substitute

Tn = 97+(n - 1)(4)

Tn = 97 + 4n -4

Tn = 4n + 93

Similarly for the distances 49 cm, 47 cm, 45cm .....

This also forms an arithmetic sequence and the nth term is expressed as:

Tn = a + (n - 1)d

a is the first term = 49

d is the common difference = 2

Substitute

Tn = 49+(n - 1)(2)

Tn = 49 + 2n -2

Tn = 2n + 47

For the particles to meet, this means that 4n + 93 = 2n + 47

4n - 2n = 47 - 93

2n = -46

n = -23

This shows that it will take the particle 23 secs to meet.

To get the distance travelled by each particle

Tn = 4n + 93

T2 = 4(2) + 93

T2 = 101

For the other sequence;

Tn = 2n + 47

T2 = 2(2) + 47

T2 = 51

Taking the difference;

D = 101 - 51 = 50cm

Hence the distance travelled by each particle is 50cm

Learn more here: brainly.com/question/13989292

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