Answer:
Step-by-step explanation:
Let x represent the number of apples that she wants to buy.
The grocery store sells apples for $1 each and mangos for $0.50 each.
If Gabriella decided to buy 13 mangos, it means that the cost of buying x apples and 13 mangoes is expressed as
x + 13 × 0.5 = x + 6.5
If she buy at least 19 apples, it means that
x + 13 ≥ 19
x ≥ 19 - 13
x ≥ 6
Gabriella has $15 to spend. It means that
x + 6.5 ≤ 15
x ≤ 15 - 6.5
x ≤ 8.5
Therefore, the maximum number of apples that she can buy is 8
Answer:
2x+3(10+x)
Step-by-step explanation:
I'm not sure but I think this might be the answer
Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
<u>4(x + 2) + 3 >= 27</u>
4x + 8 + 3 >= 27
4x + 11 >= 27
4x >= 16
<u>x >= 4</u>
