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Sergio039 [100]
3 years ago
13

A 2.50 L balloon is filled with water at 2.27 atm. If the balloon is squeezed into a 0.80 L beaker and does NOT burst, what is t

he pressure of water in the balloon?
Chemistry
2 answers:
rewona [7]3 years ago
4 0

Answer:

7.1 atm

Using Boyle’s law, P1 V1=P2 V2.

Ludmilka [50]3 years ago
3 0

Answer:

P_2=7.09atm

Explanation:

Hello!

In this case, given the change in volume and pressure of the gas, it is possible for us to recall the Boyle's law as way to understand the inversely proportional relationship between pressure and volume:

P_1V_1=P_2V_2

Thus, when solving for the final pressure, P2, given the initial pressure and volume and the final volume, we obtain:

P_2=\frac{P_1V_1}{V_2}\\\\P_2=\frac{2.27atm*2.50L}{0.80L}\\\\P_2=7.09atm

Best regards!

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t1/2 = 10 min = 0.693 / λ

Hence, λ = 0.693 / 10 min              -         (1)

Nt = Nο e∧(-λt)    
                
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by rearranging the equation,
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From (1) and (2),

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= (Nt/Nο ) x 100%
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= 3.6138x10^24 atoms.

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