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lys-0071 [83]
2 years ago
8

Hydrogen chloride gas is shipped in a container under 5,100 mmHg of pressure that occupies 20.1 liters at 29°C. How many liters

of gas would be produced at STP?
Chemistry
2 answers:
natulia [17]2 years ago
7 0
<span>The standard temperature and pressure is 273.15 K and 1 atm. We use the ideal gas equation to solve this problem to find for the amount of gas in moles.

PV = nRT
n = PV / RT = 5100 mmHg x 20.1 L / </span>62.364<span> x 302.15
n = 5.44 mol

At STP,

V = nRT / P = </span><span>5.44 mol x</span> 62.364 x 273.15 / 760
V = 121.94 L<span>
</span>
Gnoma [55]2 years ago
3 0

The  number  of liters  of a gas  that  would  produced at STP is  121.86  Liters


<u><em>calculation</em></u>

<em>Step 1 </em><em><u>: </u></em> calculate the  moles  of  hydrogen  chloride  gas  using  ideal gas  equation

That is PV=nRT  where,

P( pressure) = 5100 mm hg

V(volume)= 20.1 L

n(number of moles)= ? moles

R( gas constant) =  62.3636 L.mmhg/mol.K

T( temperature) =29 °C  in to kelvin = 29 +273 =302 K


by making n  the subject  of the formula by diving both side  by RT

n= Pv/RT

n=[(5100 mm hg x20.1 L)/(62.3636 l.mmhg/mol.k x 302 K)]  =5.44 moles


Step : calculate  the  liters  of a gas at STP

that is at STP

   1 moles  = 22.4 L

5.44  moles=? L

by cross multiplication

=( 5.44 mole  x 22.4 L)  / 1 mole =121.86  liters


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820.864 g

Explanation:

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8 × 32.065 = 256.52 g/mol

2) To find the mass use the formula:

m = n × M where <em>m</em><em> </em>is the mass, <em>n</em><em> </em>is the number of moles, and <em>M</em><em> </em>is the molar mass.

3)

m \: = 3.2 \times 256.52

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2 years ago
How many types of ions must be present in solution, at minimum, for the phenomenon of selective precipitation to be observed? Yo
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Answer:

Two (2) types of ions

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Majorly, the process determines the metal ions present by initiating precipitation as certain conditions.

I hope this was helpful.

7 0
3 years ago
Why do the metals Co, Rh, and Lr form octahedral complexes (rather than tetrahedral or square planar complexes)? Hint: Look at t
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Explanation:

Octahedral complexes will be favoured over tetrahedral ones because:

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6 0
2 years ago
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride
IrinaK [193]

The question is incomplete, here is the complete question:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed? Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of hydrogen chloride produced in the reaction will be 4.4 mL

<u>Explanation:</u>

We are given:

Volume of methane gas = 1.1 mL

The chemical equation for the reaction of methane gas and chlorine gas follows:

CH_4(g)+4Cl_2(g)\rightarrow 4HCl(g)+CCl_4(g)

Moles of methane gas = 1 mole

Moles of hydrogen chloride gas = 4 moles

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the volume and number of moles of methane gas

V_2\text{ and }n_2 are the volume and number of moles of hydrogen chloride

We are given:

V_1=1.1mL\\n_1=1mol\\V_2=?L\\n_2=4mol

Putting values in above equation, we get:

\frac{1.1}{1}=\frac{V_2}{4}\\\\V_2=\frac{1.1\times 4}{1}=4.4mL

Hence, the volume of hydrogen chloride produced in the reaction will be 4.4 mL

5 0
2 years ago
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