Question

Hydrogen chloride gas is shipped in a container under 5,100 mmHg of pressure that occupies 20.1 liters at 29°C. How many liters of gas would be produced at STP?

Answer 1

The standard temperature and pressure is 273.15 K and 1 atm. We use the ideal gas equation to solve this problem to find for the amount of gas in moles.

PV = nRT
n = PV / RT = 5100 mmHg x 20.1 L / 62.364 x 302.15
n = 5.44 mol

At STP,

V = nRT / P = 5.44 mol x 62.364 x 273.15 / 760
V = 121.94 L

Answer 2

The  number  of liters  of a gas  that  would  produced at STP is  121.86  Liters

calculation

Step 1 : calculate the  moles  of  hydrogen  chloride  gas  using  ideal gas  equation

That is PV=nRT  where,

P( pressure) = 5100 mm hg

V(volume)= 20.1 L

n(number of moles)= ? moles

R( gas constant) =  62.3636 L.mmhg/mol.K

T( temperature) =29 °C  in to kelvin = 29 +273 =302 K

by making n  the subject  of the formula by diving both side  by RT

n= Pv/RT

n=[(5100 mm hg x20.1 L)/(62.3636 l.mmhg/mol.k x 302 K)]  =5.44 moles

Step : calculate  the  liters  of a gas at STP

that is at STP

   1 moles  = 22.4 L

5.44  moles=? L

by cross multiplication

=( 5.44 mole  x 22.4 L)  / 1 mole =121.86  liters