Answer:
See Explanation
Explanation:
The equation of the reaction is;
C7H16(g) + 11O2(g) ---->7CO2(g) + 8H2O(g)
1a) Number of moles in 228 g of H2O = 228 g/18 g/mol = 12.67 moles
From the reaction equation;
11 moles of O2 yields 8 moles of H2O
x moles of O2 yields 12.67 moles of H2O
x = 11 * 12.67/8
x = 17.4 moles of O2
Since 1 mole of O2 occupies 22.4 L
17.4 moles of O2 occupies 17.4 moles * 22.4 L/1 mole = 389.76 L
1b) Molar mass of C7H16 = 100 g/mol
Number of moles in 300 g of C7H16 = 300 g/100g/mol = 3 moles
1 mole of C7H16 yields 7 moles of CO2
3 moles of C7H16 yields 3 * 7/1 = 21 moles of CO2
If 1 mole of CO2 occupies 22.4 L
21 moles of CO2 occupies 21 moles * 22.4 L/1 mole = 470.4 L of CO2
2) Number of moles in 202 L of H2 is obtained by;
1 mole of H2 occupies 22.4 L
x moles of H2 occupies 202 L
x = 1 mole * 202 L/22.4 L = 9 moles of H2
From the reaction equation;
3 moles of H2 yields 2 moles of PH3
9 moles of H2 will yield 9 * 2/3 = 6 moles of PH3
Mass of 6 moles of PH3 = 6 moles of PH3 * 34 g/mol = 204 g of PH3
