Using the figure, find the missing values. Round each value to the nearest whole number.

Help me please fast and please explainnnnnn

alexira [117]

Answer:

I'm pretty sure it's 1 cup of water

You need 2 cups of pancake mix more than water so if you have 3 cups of pancake mix then you'd need 1 cup of water.

6 cups of mix = 4 cups of water

the cups of the mix is are 2 more cups than the water

3 cups of mix = 1 cup of water

I hope that helps and good luck! :)

5 0

3 years ago

Find the slope of the line through the points (-2,5) and (-6,-3)

Westkost [7]

Answer:

slope = 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 6, - 3)

m = $\frac{-3-5}{-6+2}$ = $\frac{-8}{-4}$ = 2

6 0

4 years ago

The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard

dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2$

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{106.8 - 104}{2}$

$Z = 1.4$

$Z = 1.4$ has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0

4 years ago

X is 13 units to the left of the zero. -x is ? units to the ? of zero

aniked [119]

-x is 13 units to the right of 0 or -13 units to the left of 0.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

In triangle XYZ, side XY measures 6 inches, side YZ measures 8 inches, and side XZ measures 10 inches. List the angles of the tr

olganol [36]

we have that

In triangle XYZ,
side XY measures 6 inches,
side YZ measures 8 inches,
side XZ measures 10 inches

let
a--------> side XY------> 6 in
b--------> side YZ------> 8 in
c--------> side XZ-----> 10 in
A--------> angle YZX
B-------> angle YXZ
C-------> angle XYZ
we know that
we can apply the Cosine Law to find the angles of the triangle.

find angle C
c²=a²+b²-2ab*cosC
cos C=(a²+b²-c²)/(2ab)--------> cos C=(6²+8²-10²)/(2*6*8)
cos C=0
C=arc cos (0)-----------> C=90°

find angle B
b²=a²+c²-2ac*cosB
cos B=(a²+c²-b²)/(2ac)--------> cos B=(6²+10²-8²)/(2*6*10)
cos B=0.60
B=arc cos (0.60)-----------> B=53.12°

A+B+C=180---------> A=180-(B+C)-------> A=180-(90+53.12)
A=36.88°

the answer is
<span>the angles of the triangle in order from largest angle to smallest angle are
C=90</span>°-------> angle XYZ
B=53.12°----> angle YXZ
A=36.88°----> angle YZX

7 0

4 years ago