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jek_recluse [69]
3 years ago
14

Move two choices to the blanks to correctly complete the sentences.

Mathematics
1 answer:
Pavel [41]3 years ago
6 0

Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

S = \{HH,HT,TH,TT\} -- Sample Space

n(S) = 4 --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{1}{4}

Multiply this by the number of tosses

P(HT) * n= \frac{1}{4} * 20

P(HT) * n= 5

<em></em>

Solving (b); experimental probability of HT

Here, we make use of the table

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{6}{20}

P(HT) = 0.30 ---- Experimental Probability

In (a), the theoretical probability is:

P(HT) = \frac{1}{4}

P(HT) = 0.25 ---- Experimental Probability

By comparison;

0.30 > 0.25

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3 years ago
If f(x)=2x-5, which expression represents f(x+1)? A) 2x-3, B) 2x-4, C)2x-5, D)2x+7
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i solve two of ur problems.
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3 years ago
Help plz! (a + b - c)(a + b + c) multiplying polynomials
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Step-by-step explanation:

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Give answer in standard form for part a and b
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3 years ago
Items produced by a manufacturing process are supposed to weigh 90 grams. The manufacturing procon
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Using the normal distribution, it is found that 0.26% of the items will either  weigh less than 87 grams or more than  93 grams.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 90 grams, hence \mu = 90.
  • The standard deviation is of 1 gram, hence \sigma = 1.

We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{3}{1}

Z = 3

The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.

  • Looking at the z-table, Z = -3 has a p-value of 0.0013.

2 x 0.0013 = 0.0026

0.0026 x 100% = 0.26%

0.26% of the items will either  weigh less than 87 grams or more than  93 grams.

For more on the normal distribution, you can check brainly.com/question/24663213

4 0
3 years ago
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