Given:
The population, P, of six towns with time t in years are given by the following exponential equations:
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(vi) 
To find:
The town whose population is decreasing the fastest.
Solution:
The general form of an exponential function is:
Where, a is the initial value, b is the growth or decay factor.
If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.
The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town is decreasing the fastest.
Therefore, the correct option is b.
Answer:
Let c represent the number of cows
Let h represent the number of horses
There are 2 more horses than cows in a field
⇒there are extra two horses are always than cows
⇒ horses-cows =2
⇒ hourses=2+cows
⇒ h =2+c
There are 16 animals in the field in all.
⇒ h +c=16
⇒ (2+c)+c=16
⇒ 2+2c=16
⇒ 2+2c-2=16-2
⇒2c=16-2
⇒ 2c=14
c=7
Step-by-step explanation:
The answer is
<span>D) If x=19, then 2x-3=35
proof
</span>
If x=19, 2(19)-3=38-3=35 so <span> If x=19, then 2x-3=35 is verified
</span>if <span>2x-3=35, so </span><span>2x=35 + 3, </span><span><span>2x=38 implies x = 19, so x =19 is verified
</span> </span>
<span>If x=19 if and only if 2x-3=35
</span>
Answer:
a) Undefined.
Step-by-step explanation:
Answer:
Change your name, unmute your microphone, and play rickroll
Step-by-step explanation:
YAAAAA
