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3 years ago

If measure angle acd=70 then measure angle bcd=

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

8 0

Answer: 35

Step-by-step explanation:

Angle ACD = 70

Angle BCD = 70/2 = 35

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Westkost [7]

-5 = n + 14
So, n = -19

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3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

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2 years ago

Which expression gives the value of x?

melisa1 [442]

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3 years ago

Read 2 more answers

What is the ratio 18 to 27 written as a fraction in lowest terms?

Studentka2010 [4]

$18:27=\dfrac{18}{27}=\dfrac{18:9}{27:9}=\dfrac{2}{3}=2:3$

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4 years ago

Question below ------------------------------

Ludmilka [50]

Answer:

<h2>The first one is the answer</h2>

Step-by-step explanation:

Hope im correct can you brainliest me?

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2 years ago