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3 years ago

If measure angle acd=70 then measure angle bcd=

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

8 0

Answer: 35

Step-by-step explanation:

Angle ACD = 70

Angle BCD = 70/2 = 35

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Solve 7/3 x 3/7=-2/3(3/7). X=

almond37 [142]

Answer:

x= 2/7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7/3x 3/7=2/3(3/7)

so 2/7

7 0

4 years ago

Simplify (7^5)^3<br> A.7^8<br> B.(1/7)^15<br> C.35^3<br> D.7^15

oksano4ka [1.4K]

Answer:

$\red{{7}^{15} }$

Step-by-step explanation:

We know that,

${x}^{a} \times {x}^{b} = {x}^{a + b} \\ ( {x}^{a} ) ^{b} = {x}^{ab}$

Accordingly,

$( {7}^{5} ) ^{3} \\ {7}^{5 \times 3} \\ {7}^{15}$

8 0

2 years ago

Bacteria usually reproduce by a process called binary fission. In this type of reproduction, one bacterium divides to

Fed [463]

Answer:

$\large \boxed{\text{0.0462 min}^{-1}}$

Step-by-step explanation:

One formula for the reproduction of bacteria is

$\dfrac{N}{N_{0}} = e^{kt}$

Data:

N = 2

N₀ = 1

t = 15 min

Calculation:

$\begin{array}{rcl}\dfrac{N}{N_{0}}& =& e^{kt}\\\\\dfrac{2}{1}& = & e^{k\times15 \text{ min}}\\\\2 & = & e^{15k \text{ min}}\\\ln 2 & = & 15k \text{ min}\\k & = & \dfrac{\ln2 }{\text{15 min}}\\\\& = & \textbf{0.0462 min}^{\mathbf{-1}}\\\\\end{array}\\\text{The value of the constant k is $\large \boxed{\textbf{0.0462 min }^{\mathbf{-1}}}$}$

6 0

4 years ago

Members of the track team can run 400 min an average time of 64.6 seconds. The

vova2212 [387]

Answer:

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

Step-by-step explanation:

Calculation for the equation that can be

use to find the maximum and minimum times for the track team

Using this equation to find the maximum times for the track team

T maximum=T average -7.8 seconds

T maximum=64.6 seconds-7.8 seconds

Using this equation to find the minimum times for the the track team

T minimum=T average +7.8 seconds

T minimum=64.6 seconds +7.8 seconds

Therefore the equation for the maximum and minimum times for the track team are :

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

6 0

3 years ago

Read the problem and examine the diagram. Fletcher got 92 votes in the class election. 115 people voted. What percent of all the

Rzqust [24]

80%.

92/115= .8

.8•100= 80(%)

5 0

3 years ago