Answer:
Step-by-step explanation:
If Δ JKL ~ Δ JHG , then
= 
≠ 
⇒ triangles are not similar
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Y = sin(x^2)
Use the chain rule.
We want dy/dx.
dy/dx = cos(x^2)*2x
dy/dx = 2xcos(x^2)
Did you follow?
Answer:
Y= -3/5x - 3
Step-by-step explanation:
3x+5y=-15
-3x. -3x
5y=-3x-15 then you would divide 5 from all the numbers to get : y=-3/5x-3.
The correct answer is A=33,000(0.82)^t
I know this because I did the work. ;)
Have a great life! ^v^
