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Anit [1.1K]
3 years ago
13

What are the dimensions of the rectangle shown on the coordinate plane?The base is 5 units and the height is 3 units.The base is

4 units and the height is 7 units.The base is 7 units and the height is 5 units.The base is 7 units and the height is 3 units.
Mathematics
1 answer:
stepan [7]3 years ago
6 0

Answer:

Identify the radius and the center of a circle whose equation is (x – 5)² + y² = 81.

Step-by-step explanation:

The radius of the circle is  

⇒ 9 units.

The center of the circle is at (

⇒ 5,  

⇒ 0).

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Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e
netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

F(x)=\frac{e^x-1-x}{x^2}

When,

x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281

x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885

x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091

x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438

x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)

Correct upto six decimal places.

Now,

\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}   (\frac{0}{0}) form, applying L-Hospital rule that is differentiating numerator and denominator we get,

\lim_{x\to 0}F(x)

=\lim_{x\to 0}\frac{e^x-1}{2x}    (\frac{0}{0}) form.

=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).  

8 0
3 years ago
A circular garden has a circumference of
omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: 2\pir. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

d\pi

So, solving for both the radius and the diameter gives us:

d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2

So, the length of thes traight path that goes through the center of the guardain is just 8xy^2, and we can use the radius for the next part of the problem.

The area of a circle is \pi r^2, which means we can just plug in the radius and find our area:

A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4

So, we have found our area(16 \pi x^2 y^4) and the problem is done.

6 0
4 years ago
When x2+3x-4 is subtracted from x (x2+3x-2) what is the difference
tankabanditka [31]
I'm assuming this is x^2 + 3x - 4 and x(x^2 + 3x - 2)

1.) First distribute x(x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.

2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing -1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.

3.) -1(x^2 + 3x - 4) = -x^2 - 3x + 4

4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)

5.) x^3 + 2x^2 - 5x + 4 is your final answer.

5 0
4 years ago
Read 2 more answers
I know he is incorrect but I just can’t say why please help
egoroff_w [7]

Answer:


Step-by-step explanation:

Umm, Wheres Tanner's graph? Please post it so that I could answer your question!! :)

3 0
3 years ago
Which one is bigger 95.580 or 95.58
mezya [45]
They're both equal. The zero in 95.580 doesn't matter in this comparison.
5 0
3 years ago
Read 2 more answers
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