3 years ago

PLEASE HELP ASAP!!! i’ll mark brainlest

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

It owuld be 3 cuz the least significant digit would be used to determine the precision right? So it would be 3!

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$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

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On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

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