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Eva8 [605]
3 years ago
6

The length of a rectangle is 3 times the width. The perimeter is 120 meters Find the length and width.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

10

Step-by-step explanation:

I think that it is 10 because it would have to be a rectangle or square to find the perimeter. So first I divided 120 by 4 and then got 30. Then I divided 30 by 3 and got 10. So, this is why I think it is 10.

120/4 = 30

30/3 = 10

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dezoksy [38]

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3 years ago
What is the area of the base in the figure below? A cylinder with height 12 and diameter 6.
Naya [18.7K]

Answer:

About 28.27.

Step-by-step explanation:

To figure out the area of the base, you just use the formula to find the area of a circle. Which is;

A = r^2 * pi

(r stands for radius)

3 0
4 years ago
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Thepotemich [5.8K]

Answer:I don't know this one

Step-by-step explanation:

4 0
3 years ago
Find a power series for the function, centered at c, and determine the interval of convergence. f(x) = 9 3x + 2 , c = 6
san4es73 [151]

Answer:

\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ........

The interval of convergence is:(-\frac{2}{3},\frac{16}{3})

Step-by-step explanation:

Given

f(x)= \frac{9}{3x+ 2}

c = 6

The geometric series centered at c is of the form:

\frac{a}{1 - (r - c)} = \sum\limits^{\infty}_{n=0}a(r - c)^n, |r - c| < 1.

Where:

a \to first term

r - c \to common ratio

We have to write

f(x)= \frac{9}{3x+ 2}

In the following form:

\frac{a}{1 - r}

So, we have:

f(x)= \frac{9}{3x+ 2}

Rewrite as:

f(x) = \frac{9}{3x - 18 + 18 +2}

f(x) = \frac{9}{3x - 18 + 20}

Factorize

f(x) = \frac{1}{\frac{1}{9}(3x + 2)}

Open bracket

f(x) = \frac{1}{\frac{1}{3}x + \frac{2}{9}}

Rewrite as:

f(x) = \frac{1}{1- 1 + \frac{1}{3}x + \frac{2}{9}}

Collect like terms

f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2}{9}- 1}

Take LCM

f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2-9}{9}}

f(x) = \frac{1}{1 + \frac{1}{3}x - \frac{7}{9}}

So, we have:

f(x) = \frac{1}{1 -(- \frac{1}{3}x + \frac{7}{9})}

By comparison with: \frac{a}{1 - r}

a = 1

r = -\frac{1}{3}x + \frac{7}{9}

r = -\frac{1}{3}(x - \frac{7}{3})

At c = 6, we have:

r = -\frac{1}{3}(x - \frac{7}{3}+6-6)

Take LCM

r = -\frac{1}{3}(x + \frac{-7+18}{3}+6-6)

r = -\frac{1}{3}(x + \frac{11}{3}+6-6)

So, the power series becomes:

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}ar^n

Substitute 1 for a

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}1*r^n

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}r^n

Substitute the expression for r

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}(-\frac{1}{3}(x - \frac{7}{3}))^n

Expand

\frac{9}{3x + 2} =  \sum\limits^{\infty}_{n=0}[(-\frac{1}{3})^n* (x - \frac{7}{3})^n]

Further expand:

\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ................

The power series converges when:

\frac{1}{3}|x - \frac{7}{3}| < 1

Multiply both sides by 3

|x - \frac{7}{3}|

Expand the absolute inequality

-3 < x - \frac{7}{3}

Solve for x

\frac{7}{3}  -3 < x

Take LCM

\frac{7-9}{3} < x

-\frac{2}{3} < x

The interval of convergence is:(-\frac{2}{3},\frac{16}{3})

6 0
3 years ago
Matt decided to go out to eat. He ordered a soda for $2.15, some chicken for $8.77 and a slice of cake for $4.10. What would his
nikklg [1K]

Answer:  $ 17.72

Step-by-step explanation:

Cost of soda = $2.15 , Cost of chicken = $8.77 , Cost of slice of cake = $4.10.

Total bill amount = (Cost of soda ) + (Cost of chicken) +(Cost of slice of cake)

= $ (2.15 + 8.77 +4.10)

= $ 15.02

Tip amount = 18% of Total bill amount

= 0.18 (15.02)

= $ 2.7036 ≈  $2.70

Entire bill = Total bill amount  + Tip amount

= $ ( 15.02+2.70)

= $ 17.72

Hence, entire bill = $ 17.72

7 0
3 years ago
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