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Nookie1986 [14]
3 years ago
10

The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour

Mathematics
1 answer:
yan [13]3 years ago
4 0

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

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Answer:

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Step-by-step explanation:

To find the value for m, we first have to consider the formula for calculating simple interest.

The formula that we generally use is:

I = Prt

Now we have to find the value for t as it is not given.

We now define the different variables that we do have.

P = 860

I = 838.50

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First we substitute the value that we do have in the formula.

838.50 = 860 (0.06) (t)

838.50 = 51.6 (t)

838.50 = 51.6t

Now we have to divide both sides by 51.6 to find the value of t.

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Now that we have all the values, we can check if the number months is correct by doing the formula again.

I = Prt

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I = 860 (0.975)

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3 years ago
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Answer:

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Step-by-step explanation:

Let 'x' be the missing sides.

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cross multiplication

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Answer:

Step-by-step explanation:

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