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Nookie1986 [14]
2 years ago
10

The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour

Mathematics
1 answer:
yan [13]2 years ago
4 0

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

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Line l and line m are straight lines. What is the measure of angle y?
qwelly [4]

Answer: 190

Step-by-step explanation:

8 0
3 years ago
Whats the simpilest form of the ratio <br>48 min to 3 hours.​
MArishka [77]

15:4.

Step-by-step explanation:

1 hour = 60 min

3 hours = 60 x 3 = 180 min

Ratio:

180/48

Simplest form 15/4

Therefore, the simplest form of the ratio will be 15:4

7 0
3 years ago
Read 2 more answers
At bike shop x it costs $2.75 per hour plus a $3.00 deposit to rent a bike. at bike shop z it costs $1.75 per hour plus a $7.00
dem82 [27]

Answer:

Multiply the rate per hour by the number of hours (n) and add the deposit.

A)

Bike shop x: c = 2.75n + 3.00

Bike shop z: c = 1.75n + 7.00

B) to find when they will cost the same set the equations equal to each other and solve for n:

2.75n + 3.00 = 1.75n + 7.00

Subtract 3 from each side:

2.75n = 1.75n + 4.00

Subtract 1.75n from both sides:

1.00n = 4.00

Divide both sides by 1:

n = 4 hours

6 0
2 years ago
Read 2 more answers
Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
2 years ago
On monday caroline spent 2/3hour riding her bike and 1 3/4 doing homework how many more hours did caroline spend doing homework
Andrej [43]
2/3 hour is 40 minutes. 1 3/4 hour is 1 hour and 45 minutes. So she spent 1 hour and 5 minutes or 1 1/12 hour longer doing homework.
8 0
3 years ago
Read 2 more answers
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