Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right?
Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!!
So
A={51,53,57,59,61......99}
B={55,60,65,70.......95} [We stop till 100 because set A has no such element]
So what is A ∩ B here?
A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}
</span>
Answer:
rectagular
Step-by-step explanation:
<h3>Given:</h3>
- Radius of 50 point region= 3 in
- Width of other regions= 4 in
<h3>To find:</h3>
The area of the target which earns 30 points on a throw.
<h3>Solution:</h3>
Let's solve
We have to find the answer in terms of π so, we'll just have to multiply the radius by itself.
<u>Hence,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the target which earns 30 points on a throw</u><u> </u><u>is</u><u> </u><u>4</u><u>9</u><u>π</u><u> </u><u>square</u><u> </u><u>inches</u><u>.</u>
<u>Answer</u><u>=</u><u> </u><u>Option</u><u> </u><u>B</u>
-3(6)-2-(-4(6)+10)
-3(6)-2-(-24+10)
-18-2--14
answer is -6
6y - 3x > 9
-3x > -6y + 9
x < 2y - 3....yes, it is shaded below the line
