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Inessa05 [86]
3 years ago
11

One final question, what would be the proper way to write this? I thought it was the last one answer but I’m not sure

Mathematics
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

OMG NO- KEEP IT THAT WAY

You're already right! :)

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Answer: Can you show the full question.

Step-by-step explanation:

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Find the GCF of 2m^5 and 28m4<br> a. 28m^4<br> b. m^4<br> c. 2m^4<br> d. 2m
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Select all the equations on which the point (10, 0) lies.
lilavasa [31]

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The answer to this problem is B, C, and E.

Step-by-step explanation:

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Someone pls help me due in 30 min. Given that x and y show inverse variation, complete the table.
aivan3 [116]

Answer:

1st blank=y_{1}

2nd blank=x_{1}

3rd blank= y_{2}

3*27=81

so 1*y_{1}=81

hence y_{1}=81

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x_{1}=9

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<em>Hope this helps.</em>

<em>Please mark me as brainliest.</em>

8 0
3 years ago
Based on the question
nlexa [21]

From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)

In this problem, we have that:

  • To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
  • To the right of x = 3, that is, for values that are greater than x = 3, f(x) -> 4.

Hence the lateral limits are given as follows:

  • \lim_{x \rightarrow 3^-} f(x) = -3
  • \lim_{x \rightarrow 3^+} f(x) = 4

Since the lateral limits are different, the limit does not exist.

More can be learned about lateral limits at brainly.com/question/26270080

#SPJ1

8 0
2 years ago
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