Hello from MrBillDoesMath!
Answer:
I think your formula (2y/x2) is equivalent to
(2*y)/(x^2) where x^2 means x-squared.
If so, then
(2*y)/(x^2) = (2*3)/(4*4) = 6/16 = 3/8
Thank you,
MrB
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
(x+2)(x-2)(x-3) is the answer hope you 've an A
1/4, because you disregard the repeating 25s and round, and 25 x 4 is one hundred, so simplified it's 1/4.
<h3>I'll teach you how to solve 125 1/3</h3>
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125 1/3
Convert mixed numbers to improper fractions:
125 1/3=
125*3+1/3=
376/3
Your Answer Is 376/3
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