What is the formula for trioxocarbonate (IV)
1 answer:
Answer:
Explanation:
Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.
All sodium, potassium, and ammonium of trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.
Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.
The formula for Trioxocarbonate (iv) is:
So, we can have Sodium trioxocarbonate as and sodium hydrogen trioxocarbonate (iv)
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Answer:
4.06 mol H₂O
Explanation:
- 2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
First we <em>convert the given masses of reactants into moles</em>, using <em>their respective molar masses</em>:
- 250 g O₂ ÷ 32 g/mol = 7.81 mol O₂
- 50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄
Now we <u>calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles</u>, using the <em>stoichiometric coefficients of the reaction</em>:
- 0.58 mol C₆H₁₄ *
= 5.51 mol O₂
As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that <em>C₆H₁₄ is the limiting reactant</em>.
Now we can <u>calculate how much water can be formed</u>, using <em>the number of moles of the limiting reactant</em>:
- 0.58 mol C₆H₁₄ *
= 4.06 mol H₂O