Given :
0.00072 M solution of 
at 
.
To Find :
The concentration of 
and pOH .
Solution :
1 mole of gives 2 moles of ions .
So , 0.00072 M mole of gives :
![[OH^-]=2 \times 0.00072\ M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2%20%5Ctimes%200.00072%5C%20M)
![[OH^-]=0.00144\ M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.00144%5C%20M)
![[OH^-]=1.44\times 10^{-3}\ M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.44%5Ctimes%2010%5E%7B-3%7D%5C%20M)
Now , pOH is given by :
![pOH=-log[OH^-]\\\\pOH=-log[1.44\times 10^{-3}]\\\\pOH=2.84](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D%5C%5C%5C%5CpOH%3D-log%5B1.44%5Ctimes%2010%5E%7B-3%7D%5D%5C%5C%5C%5CpOH%3D2.84)
Hence , this is the required solution .
Answer:
Number of moles of Fe = 10 mol
Number of moles of CO₂ = 15 mol
Explanation:
Given data:
Number of moles of iron oxide = 5 mol
Number of moles of carbon monoxide = 25 mol
Number of moles of product = ?
Solution:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Now we will compare the moles of reactant with product.
Fe₂O₃ : Fe
1 : 2
5 : 2×5 = 10 mol
Fe₂O₃ : CO₂
1 : 3
5 : 3×5 = 15 mol
CO : Fe
3 : 2
25 : 2/3×25 = 16.7 mol
CO : CO₂
3 : 3
25 : 25
Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.
Answer:
5.5 moles of sodium are produced
Explanation:
Given data:
Number of moles of hydrogen = 2.75 mol
Number of moles of Na produced = ?
Solution:
Chemical equation:
H₂ + 2NaCl → 2HCl + 2Na
Now we will compare the moles of hydrogen and sodium from balance chemical equation:
H₂ : Na
1 : 2
2.75 : 2/1×2.75 = 5.5 mol
Thus, 5.5 moles of sodium are produced.
Answer:
2.4 capsules
Explanation:
You are to give ampicillin, with a recommended dose of 25 mg/kg (25 mg of ampicillin per kg of body weight), to a child with a mass of 24 kg. The mass of ampicillin to be given is:
24 kg body mass × (25 mg ampicillin/ 1 kg body mass) = 600 mg ampicillin
The stock on hand is 250 mg/capsule (250 mg ampicillin per capsule). The number of capsules required to supply 600 mg of ampicillin is:
600 mg ampicillin × (1 capsule/250 mg) = 2.4 capsule
Answer:
3 × 10¯¹⁰
Explanation:
9×10² ÷ 3×10¹²
The above expression can be evaluated as follow:
9×10² ÷ 3×10¹²
Recall:
3² = 9
3¹ = 3
Therefore,
9×10² ÷ 3×10¹² = 3²×10² ÷ 3¹×10¹²
Recall:
y^m ÷ y^n = y^(m – n)
Therefore,
3²×10² ÷ 3×10¹² = 3²¯¹ × 10²¯¹²
= 3¹ × 10¯¹⁰
Recall:
y¹ = y
Therefore,
3¹ × 10¯¹⁰ = 3 × 10¯¹⁰
Therefore,
9×10² ÷ 3×10¹² = 3 × 10¯¹⁰
