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3 years ago

If Shane weighs 120 pounds and Johnny weighs 150 pounds.If Shanie gains 60 pounds will Shanie and Johnny be the same weight.

Mathematics

2 answers:

just olya [345]3 years ago

3 0

Answer:

shane is 120 pounds and johnny is 150 pounds

Step-by-step explanation:

shane 120 and johnny gains weight 60 pounds so 120 plus 60 that is both of the together is 180 hope this helps you i think they maybe be the same weight because together they are more

Svetllana [295]3 years ago

3 0

Answer:

No, Shane will be heavier

Step-by-step explanation:

120 > 150

120 + 60= 180

180 > 150

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nydimaria [60]

Answer:

The length of each red rod is 10 cm and the length of each blue rod is 14 cm

Step-by-step explanation:

Let

x ----> the length of each red rod in centimeters

y ----> the length of each blue rod in centimeters

we know that

$3x=2y+2$ ----> equation A

$3y=4x+2$ ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is the point (10,14)

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The length of each red rod is 10 cm and the length of each blue rod is 14 cm

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Step-by-step explanation:

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3 years ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Josiah has punch c

love history [14]

Let x be the number of weeks; therefore, the two linear equations are

$\begin{gathered} T=2+7x \\ \text{and} \\ C=11+4x \end{gathered}$

Where T stands for the punches on the tea punch card and C for the punches on the coffee punch card.

Solving by substitution. Set T=C, then

$\begin{gathered} T=C \\ \Rightarrow2+7x=11+4x \\ \Rightarrow3x=9 \\ \Rightarrow x=\frac{9}{3}=3 \\ \Rightarrow x=3 \end{gathered}$

Thus, substitute the value of x=3 into the first equation,

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1 year ago

A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)

marta [7]

(a) If $A,B,C$ are mutually exclusive, then

$P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0$

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$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}$

(b) If $A,B,C$ are mutually independent, then

$P(A\cap B)=P(A)P(B),$

$P(A\cap C)=P(A)P(C),$

$P(B\cap C)=P(B)P(C),$

$P(A\cap B\cap C)=P(A)P(B)P(C)$

so that

$P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)$

$P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}$

$P(A\cup B\cup C)=\dfrac35$

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3 years ago

If Shane weighs 120 pounds and Johnny weighs 150 pounds.If Shanie gains 60 pounds will Shanie and Johnny be the same weight.​

If Shane weighs 120 pounds and Johnny weighs 150 pounds.If Shanie gains 60 pounds will Shanie and Johnny be the same weight.