Let the second score = x
⇒ second score = x
<span>the first is 14 points more than the second
</span>⇒ first score = x + 14
<span>the sum of the first two is 6 more than twice the third
</span>⇒ third score = 1/2 (x + x + 14 - 6) = x + 4
<span>The sum of a student's three score is 246
</span>⇒ x + (x + 14) + (x + 4) = 246
<span>
Solve x:
</span>x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76
second score = x = 76
first score = x + 14 = 76 + 14 = 90
Answer: 90
Answer:
32
Step-by-step explanation:
v/4 -3=5
+3 so the 3's cancel out
v/4=8
x4 x4
v=32
Switch sides
4/5 (x+3)=y+6
Multiply both sides by 5
5*4/5 (x+3) = 5y+5*6
Simplify
4(x+3) = 57+30
Divide both sides by 4
4(x+3)/4 = 5y/4+ 30/4
Simplify
x+3 = 5y+30/4
Subtract 3 from both sides
x+3 - 3 = 5y+30/4 - 3
Simplify
x=5y+30/4 - 3
<span> C.<span>No, because each lime will cost a bit more than 30¢, so 4 limes will cost a bit more than $1.20.</span></span>
